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# Finding the column name for a value in a table

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Occasional Contributor

# Finding the column name for a value in a table

I have a 3x3 table with a header and two data rows as below.

A1=First, B1=Second, C1=Third
A2=1, B2=2, C2=3
A3=4, B3=5, C3=6

In cell D1 I'd like to enter a search criteria. For example 5.
Then in E1 I'd like to output the name of the header for that column. In this case Second.

Following the logic this should be the result in E1 when entering each number in D1.

1 = First
2 = Second
3 = Third
4 = First
5= Second
6 = Third

I've tried Index, Match and Vlookup without success. How can you solve this? :)

7 Replies
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# Re: Finding the column name for a value in a table

Hi Peter,

You need to the Index & Match combination to solve this!

But you need to nest another combination because you want to search the value in cell E1 in two rows!

The formula looks like this:

`=IFERROR(INDEX(A1:C3,,MATCH(D1,A2:C2,0)),INDEX(A1:C3,,MATCH(D1,A3:C3,0)))`

Hope that helps

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# Re: Finding the column name for a value in a table

That helps, thanks :)

What if I want to expand the table with more columns and rows? Is it possible to make the formula more dynamic?

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Solution

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# Re: Finding the column name for a value in a table

Thanks,

That works like a charm :) Let's say these numbers were part of a zip code.

So in E1 I would enter 38000. Instead of the part: \$A\$2:\$C\$15=\$E\$1
I'd like: \$A\$2:\$C\$15=LEFT(\$E\$1;2)

But I get a #REF! error. What can be wrong in this case?

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# Re: Finding the column name for a value in a table

Peter, LEFT returns text, wrap it with VALUE to receive number

`=OFFSET(\$A\$1,0,SUMPRODUCT((\$A\$2:\$C\$15=VALUE(LEFT(\$E\$2,2)))*COLUMN(\$A\$2:\$C\$15))-1)`

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# Re: Finding the column name for a value in a table

Works great. Thanks again :)

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You are welcome