countifs more than 2 criteria

Copper Contributor

Hello,

 

I am trying to count the type of management type using the below table using the countifs function but everytime I use more than 2 criteria I got a 0 value.

I used the following =countifs(range,"=Trust", range,"=Adur",range="2009").

Meaning I want all Trust, when the borough is Adur in 2009.

Where am I going wrong? Does the countifs function cannot handle more than 2 criteria.

 

Any help will be very much appreciatted.

 

 

 

YearBoroughManagement Type
2009Adur                                              Trust
2009Adur                                              Trust
2009Adur                                              Trust
2009Allerdale                                         Education
2009Allerdale                                         Trust
2009Allerdale                                         Education
2009Allerdale                                         Education
2009Allerdale                                         In-House
2009Allerdale                                         Trust
2009Allerdale                                         Trust
2009Allerdale                                         In-House
2009Allerdale                                         Education
2010Adur                                              Trust
2010Adur                                              Trust
2010Adur                                              Trust
2010Adur                                              Education
2010Allerdale                                         Education
2010Allerdale                                         Trust
2010Allerdale                                         Education
2010Allerdale                                         Education
2010Allerdale                                         In-House
2010Allerdale                                         Trust
2010Allerdale                                         Trust
2010Allerdale                                         Education
2010Allerdale                                         Education
2010Alnwick                                           Trust
2011Adur                                              Trust
2011Adur                                              Trust
2011Adur                                              Trust
2011Adur                                              Education
2011Allerdale                                         Education
2011Allerdale                                         Trust
2011Allerdale                                         Education
2011Allerdale                                         Education
2011Allerdale                                         In-House
2011Allerdale                                         Trust
2011Allerdale                                         Trust
2011Allerdale                                         Education
2011Allerdale                                         Education
5 Replies

Hi Vitor,

 

As i remember COUNTIFS allows up to 256 criterias. In your latest condition use "=2009"

Dear Sergei,

 

 

Many thanks for your reply.

Still does not work. Each criterion is coming from a different column so column A will be the year range, column B borough, and column C management type. When I type the function countifs

the syntax I am using is:

=countifs(column c range,"=Trust", column b range,="Adur", column a range, "=2009")

 

And I get a zero value...

Hi Vitor,

 

Please see file  attached. I used

=COUNTIFS(C2:C40,"Trust*",B2:B40,"Adur*",A2:A40,"=2009")

Trust*, Adur* since there are spaces at the end of strings, not sure that's in your file or they were added when i copy/pasted from screen. 

 

Hi @Vitor César,

 

There is no problem. Select Correct range (either specified cells or entire column) and apply

 

 

=COUNTIFS(C:C,"Trust",B:B,"Adur",A:A,"2009")

I've taken your data as A,B,C Columns respectively.

 

Yes @Vitor Leone, Check you second column and third column.

 

As per @Sergei Baklan view, I think they may contains spaces.