Forum Discussion
Get mailcontact if member of any group
Here's a fast way to do it:
$dn = (Get-MailContact your_mail_contact).DistinguishedName
Get-Recipient -Filter "Members -eq '$dn'"
This will return all DGs, mail-enabled SGs and O365 Groups the contact might be a member of. And since it's a server-side filter, you don't need to iterate over each group.
VasilMichevthe need for speed? try this...
Get-ADObject -LDAPFilter "(&(objectCategory=contact)(objectClass=contact)(memberOf=*))" -Properties Name,MemberOf,CanonicalName | ft Name,CanonicalName,memberof -wrap
- Utilizing the LDAP FIlter was smart, it allowed me to act against just the ADObjects that were Contacts with existing group memberships without rewriting the entire script. Thanks!
- Worked for me.. it was really fast!! Can you please let me know how can I get primarysmtp address of contact via above script?
This is much more efficient, I was needing members for contacts, we have huge environment so 40k of distribution lists would not be efficient to query,
I modified so
$c = get-contact (contact smtp)
Get-ADObject -Identity $c.DistinguishedName -Properties memberof |fl
and members resulted ***THANK YOU*** not sure why MS decided not to list "member of" in ECP / powershell for contacts.
The following will get you a cleaner list with all mailboxes followed by contacts $m = New-Object System.Collections.ArrayList $c = New-Object System.Collections.ArrayList Get-DistributionGroupMember GroupName | ForEach-Object { if($_.RecipientType.ToString().Contains("Mailbox") -eq $true) { $m.Add($_.Name) } else { if ($_.RecipientType.ToString().Contains( "Contact") -eq $true) { $c.Add($_.Name) } } } $m | Get-Mailbox | ft Name,For* $c | Get-MailContact | ft Name,For*
Hey Vasil,
On this here:
$dn = (Get-MailContact your_mail_contact).DistinguishedName
Get-Recipient -Filter "Members -eq '$dn'"
How would i add an input file to your script? for instance i would like to run the above cmdlets on a list of 122 people.
Thanks,
Robert
