## Forum Discussion

# Sum formula that ignores characters in a cell that aren't numbers

Hi all,

I was wondering if anyone can solve this problem for me. I'm trying to get a formula that will add the something like the following cells:

110a

21xx

7

45bbb

The formula needs to ignore the letters and only add the numbers (the answer would just be 183, no letters). The number of letters in the cell is not constant. The formula also must not delete the letters as they are counted in a different formula so just remain.

Any ideas? Totally stumped.

Thanks,

Mike

Here is with blanks

- mtarlerSilver Contributor
MikeWells13 I created a file with a number of useful Lambda Functions and one of them is SumNumsFromTxt

See attached

As variant

`sumFromTxtRange = LAMBDA(range, LET( getNumber, LAMBDA(str, LET( inNumers, CHAR(VSTACK(SEQUENCE(4, , 43), SEQUENCE(10, , 48))), chars, LAMBDA(str, MID(str, SEQUENCE(LEN(str)), 1)), addChar, LAMBDA(str, chr, str & XLOOKUP(chr, inNumers, inNumers, "") ), --REDUCE("", chars(str), addChar) ) ), SUM(MAP(range, getNumber)) ) );`

- MikeWells13Copper ContributorThank you for your reply. I've just tested this in my spreadsheet and it works exactly the way I was looking except in one circumstance. In the range I want it to calculate, sometimes some of the cells are blank, but I need it to calculate the rest. Is there a way for this to work without an error (i.e. ignore the blank cells)?

Thanks again. I'm pretty new to this depth of Excel and have never heard of the LAMBDA function before. Not entirely sure how it works!

Copy the following custom VBA function into a standard module in the Visual Basic Editor:

`Function SumNumbers(rng As Range) As Double Dim a As Variant Dim v As Variant Dim s As String Dim i As Long a = rng.Value For Each v In a s = "" For i = 1 To Len(v) If IsNumeric(Mid(v, i, 1)) Then s = s & Mid(v, i, 1) End If Next i SumNumbers = SumNumbers + Val(s) Next v End Function`

Switch back to Excel

Use the function as follows in a cell formula:

=SumNumbers(A1:A4)

where A1:A4 is a range with mixed text characters and digits.

Save the workbook as a macro-enabled workbook (*.xlsm).

Make sure that you allow macros when you open it.

- davidlealIron Contributor
MikeWells13 What about this approach?:

`=SUM(BYROW(A1:A9,LAMBDA(x,IFERROR(SUM(1*TEXTSPLIT(x, CHAR(ROW(65:132)),,1)),0))))`

It splits by letters, but you can include additional characters if that is your case. Added

**IFERROR**preventing empty cells. Iterate for all rows via**BYROW**, convert the result to a number via 1*, and sum it. The inner**SUM**is to consider the case the string can have more than one number, so we sum it, if that is not a use case, then it can be removed.Maybe it is better to split by numbers, so you don't need to deal with a large list of exclusions (non-numbers), as follows:

`=SUM(BYROW(A1:A9, LAMBDA(x, IFERROR(SUM(1*TEXTSPLIT(x,TEXTSPLIT(x,VSTACK({".";"-"}, CHAR(ROW(48:57))),,1),,1)),IF(ISNUMBER(x),x,0)))))`

The inner

**TEXTSPLIT**does it by the characters of our interest: digits plus "**.**" and "**-**" (to consider negative numbers). Then we use this result for the outer**TEXTSPLIT**as delimiters to extract just the numbers. We need to treat some special cases: 1) The string is a valid number, or it is just a text with no numbers in such situations**TEXTSPLIT**returns**#CALC!**, 2) Empty rows, returns**#VALUE!**. That is why it was added the**IFERROR**condition with an**IF**statement.Credit to mtarler for a more simplified version from previous formula:

`=SUM(BYROW(A1:A9, LAMBDA(x, IFERROR(1*x,SUM( IFERROR(1*TEXTSPLIT(x,TEXTSPLIT(x,{".";"-"}, CHAR(ROW(48:57)),1),,1),0))))))`

It tries to coerce

**x**to a number via**1***, in case the string is a valid number. If Excel can't do it, returns**#VALUE!**, that is why we use**IFERROR.****VSTACK**is not needed for the inner**TEXTSPLIT**, we can spit by row and by columns, using both group of delimiters. Then the outer**TEXTPLIT**tries to use it as list of column delimiters. The second**IFERROR**is to consider the case the string**x**has no numbers,**"."**or**"-"**.I hope it helps,

David

- mtarlerSilver Contributor
MikeWells13 i believe both SergeiBaklan and davidleal approaches basically strip out all text and give you a number from concatenating what is left. I think you want/need it to treat each embedded number separately which my attachment above does. here are the Lambda functions from that:

`SumNumsFromTxt = LAMBDA(in, SUM(BYROW(in, LAMBDA(i, SUM(--CleanNumbers(Txt2Array(ExtractNumbers(i), ";")))))) ); ExtractNumbers = LAMBDA(in, IF( ISBLANK(in), "", LET( _s, REDUCE( ";", MID(in, SEQUENCE(LEN(in)), 1), LAMBDA(prior, this, prior & IFS( ISNUMBER(SEARCH(this, "0123456789,.")), this, RIGHT(prior, 1) = ";", "", TRUE, ";" ) ) ), _m, MID(_s, 2, LEN(_s)), IF(RIGHT(_m, 1) = ";", LEFT(_m, LEN(_m) - 1), _m) ) ) ); CleanNumbers = LAMBDA(in, BYROW( in, LAMBDA(i, IFERROR( --i, IFERROR(--SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(i, ",", "?"), ".", ","), "?", "."), 0) ) ) ) ); Txt2Array = LAMBDA(string, delim, LET( _L, LEN(string), _d, IF(ISOMITTED(delim), ",", delim), _count, _L - LEN(SUBSTITUTE(string, _d, "")), IF( _count, TRIM(MID(SUBSTITUTE(string, _d, REPT(" ", _L)), SEQUENCE(_count + 1, 1, 1, _L), _L)), string ) ) );`

but as you can see it has quite a bit and especially with newer functions introduced since then could be optimized, but then again, if it works...