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Mel_G_01's avatar
Mel_G_01
Copper Contributor
Jun 01, 2021
Solved

Count of Date in Pivot Table

Hi All,

I would like to COUNT the number of days worked within this pivot table, but it is counting every line entry date.

For example this Job number is showing 12 days where it should be showing only 5

 

  • Mel_G_01 

    Creating PivotTable add data to data model

    and next in Value Field Setting select Distinct Count

    Without data model this option is not available.

  • Mel_G_01 

    Creating PivotTable add data to data model

    and next in Value Field Setting select Distinct Count

    Without data model this option is not available.

  • Mel_G_01's avatar
    Mel_G_01
    Copper Contributor

    Thank you for your suggestions.

    I have managed to get the information by including a formula into the data spreadsheet which counted only when the date changed, then refreshed the pivot table so that it showed the actual number of days worked.

    • Garth_h's avatar
      Garth_h
      Copper Contributor

      Mel_G_01 

       

      Hi Mel, I am struggling with the same issue. Would you mind sharing the formula you used to count the days / day changes.

  • tusharm10's avatar
    tusharm10
    Brass Contributor

    I'm not sure how to get what you want from a PivotTable.

    However, Excel has made several improvements over the past few years so you can do the needful on your own (assuming you have the appropriate version of Excel).

    Suppose that

    * your data are in a table as Excel understands it (Insert | Table) and

    * that the job of interest is in H2. 

    Then the 1st formula will give you a list of unique dates for the job and the 2nd formula will give you a count of the unique dates.

    =UNIQUE(FILTER(Table1[Date],Table1[Job No]=H2))

     

    =COUNTA(UNIQUE(FILTER(Table1[Date],Table1[Job No]=H2)))

     

    Mel_G_01 

  • StoneKiwi's avatar
    StoneKiwi
    Iron Contributor
    Hi,

    To count the number of UNIQUE days in the range use:
    =SUMPRODUCT(1/COUNTIF(enterRangeHere,enterRangeHere))

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