How do I find the sum of cells that are either one number or the other?

[cdiaa]

I have a spreadsheet with 2500 rows of 10 randomly generated numbers (either 1, -1, 10, -10, 100 or -100). For every row, I want 3 functions. The first would calculate the absolute value of the sum of all the 1s and -1s. The second would do the same with the 10s and -10s and then divide by 10, and the third would do the same for the 100s and -100s and then divide by 100.

I'm very new to Excel so I don't know if there's an easy way to do this that I'm just completely missing, so please help me if you can. Thank you.

[#2]

@cdiaa

Hi,

Please try these formulas:

1s and -1s

=SUMPRODUCT(IF(ABS(A1:J1)=1,ABS(A1:J1)))

10s and -10s and then divide by 10

=SUMPRODUCT(IF(ABS(A1:J1)=10,ABS(A1:J1)))/10 

100s and -100s and then divide by 100

=SUMPRODUCT(IF(ABS(A1:J1)=100,ABS(A1:J1)))/100

Hope that helps

[#3]

@cdiaa 

Your requirement is equivalent to the count of specific absolute numbers. Thus, the formula for the count of absolute 1's is: 

=SUMPRODUCT(--(ABS($A1:$J1)=1))

For 10's, the formula will be: 

=SUMPRODUCT(--(ABS($A1:$J1)=10))

For 100's, the formula will be: 

=SUMPRODUCT(--(ABS($A1:$J1)=100))

See the results of the foregoing formulas in the attached file.

[#4]

@Haytham Amairah @Twifoo Thank you, but this wasn't what I was looking for.

I meant that I want something like this:

-1 1 -1 1 1 would return the answer of 1 because -1 + 1 + (-1) + 1 + 1 = 1.

[#5 · Accepted solution]

@cdiaa

You can change the formulas as follows:

=SUMPRODUCT(IF(ABS(A1:J1)=1,A1:J1))

 =SUMPRODUCT(IF(ABS(A1:J1)=10,A1:J1))/10

=SUMPRODUCT(IF(ABS(A1:J1)=100,A1:J1))/100

[#6]

Thank you @Haytham Amairah !