Forum Discussion
MEDIAN column of AVERAGEIFS and #DIV/0!
I'm a little confused on this.
I have an array of data that was generated by conditional "AVERAGEIFS" with locations by row and differing conditions by column. The data is pulled from a different page.
=AVERAGEIFS(Data!$AL:$AL,Data!$A:$A,"FG-*",Data!$F:$F,"CRITERIA1",Data!AL:AL,"<100",Data!AL:AL,">0",Data!$G:$G,"CRITERIA2")
This part works great
I'm trying to get basic statistics on each column.
Not every location has the conditions so I have #DIV/0! errors mixed through the data.
I am trying to get the median of the column. (and am hoping STDEV functions the same way)
Despite what MS says... =MEDIAN(C4:C88) just gives me a #DIV/0! error.
I've tried multiple IF functions but it seems that having the criteria data in the same column as the range for MEDIA is causing issues.
Any ideas?
Thanks