Forum Discussion
How to create a alphanumeric sequence on vba
- Dec 27, 2022
New version:
Function nextUDI(prevUDI As String) As String 'Gera UDI com base no número anterior Dim prefixo As String Dim n As Long Dim prevVal As Long Const strAlphabet = "0123456789ABCDEFGHJKLMNPQRSTUVWXYZ" n = Len(prevUDI) prevVal = 34 * (InStr(strAlphabet, Mid(prevUDI, n - 1, 1)) - 1) + InStr(strAlphabet, Right(prevUDI, 1)) - 1 prefixo = Left(prevUDI, n - 2) nextUDI = prefixo & fBase34(prevVal + 1) End Function
Function nextUDI(prevUDI As String) As String
'Gera UDI com base no número anterior
Dim prefixo As String
Dim prevVal As Long
prevVal = Application.Decimal(Right(prevUDI, 2), 34)
prefixo = Left(prevUDI, Len(prevUDI) - 2)
nextUDI = prefixo & fBase34(prevVal + 1)
End FunctionI was using the vba code that you suggested and it was going great but the code is jumping from the 3J to 3L (I think that it is becasue I don't use "I"), from 3N to 3Q (I think that it is because I don't use "O") and from 3Y and 3Z to #value... could you help me please?
The vba code that I'm using is:
Function fBase34(ByRef lngNumToConvert As Long) As String
'Converte base 10 para 34 (base 36 sem I e O)
Dim strAlphabet As String
strAlphabet = "0123456789ABCDEFGHJKLMNPQRSTUVWXYZ"
If lngNumToConvert = 0 Then
Base34Encode = "0"
Exit Function
End If
fBase36Encode = vbNullString
Do While lngNumToConvert <> 0
fBase34 = Mid(strAlphabet, lngNumToConvert Mod 34 + 1, 1) & fBase34
lngNumToConvert = lngNumToConvert \ 34
Loop
If Len(fBase34) = 1 Then
fBase34 = "0" + fBase34
End If
End Function
Function genUDI(ByRef decNum As Long, prefixo As String) As String
'Gera UDI com base em um numero decimal
genUDI = prefixo & fBase34(decNum)
End Function
Function nextUDI(prevUDI As String) As String
'Gera UDI com base no número anterior
Dim prefixo As String
Dim prevVal As Long
prevVal = Application.Decimal(Right(prevUDI, 2), 34)
prefixo = Left(prevUDI, Len(prevUDI) - 2)
nextUDI = prefixo & fBase34(prevVal + 1)
End Function