Forum Discussion
hlookup help - structured reference
- Jul 05, 2020
1) In the formula the lookup value is entire column. Formula returns spill (an array) for which there is no place in one cell of the table, thus an error. Change on the value from current row reference.
2) Lookup range has only two columns, and you try to return the result from row 14. Thus #REF error, since there are no so many rows in the range. Change on 2.
Finally
=HLOOKUP([@[Post-Secondary Years]],$P$13:$U$14,2,TRUE)
1) In the formula the lookup value is entire column. Formula returns spill (an array) for which there is no place in one cell of the table, thus an error. Change on the value from current row reference.
2) Lookup range has only two columns, and you try to return the result from row 14. Thus #REF error, since there are no so many rows in the range. Change on 2.
Finally
=HLOOKUP([@[Post-Secondary Years]],$P$13:$U$14,2,TRUE)
- abdrose2306Oct 16, 2021Copper ContributorI have the same problem but I can’t figure out what is wrong. =HLOOKUP([Post-Secondary Years],P13:U14,2,TRUE) is the formula I have and I keep getting #SPILL!
- SergeiBaklanOct 24, 2021MVP
In this formula
=HLOOKUP([Post-Secondary Years],P13:U14,2,TRUE)
you reference entire column [Post-Secondary Years], thus HLOOKUP return the spill for which there is no space within table. Thus #SPILL! error.
Perhaps you'd like to hlookup value in current row, when it shall be
=HLOOKUP( [@[Post-Secondary Years]],P13:U14,2,TRUE)
- gltechJul 05, 2020Copper Contributoryup, thank you so much
- SergeiBaklanJul 05, 2020MVP
gltech , you are welcome
- runningincirclesOct 13, 2020Copper Contributor
SergeiBaklan I am having an issue with this question as well. I keep getting the error saying that "The syntax of this name isn't correct."
Any suggestions?