Forum Discussion
Help using index and match to find value based on 3 criteria
- Jun 30, 2019
The logic is bit unclear. You have 3 criteria - Scenario, Stock Code and Year. In source data you have no combination Stock Code=FXL and Year=1, however in answers you suggest 5% for Year=2. Why?
If ignore above formula could be
=IFERROR( INDEX($C$12:$S$15, MATCH(1,INDEX(($C$12:$C$15=C$4)*($D$12:$D$15=$C$3),0),0), MATCH(TRUE,ISNUMBER(SEARCH($C$2,$C$10:$S$10)),0)), "N/A")Couple of more comments. Your file is practically not downloadable, perhaps due to comma in name - not all system support it.
I'd recommend not to use Merging Cells. Potentially you will have lot of issues continue using merging. Alternative is - select sequential horizontal cells and apply Center Across Selection
The logic is bit unclear. You have 3 criteria - Scenario, Stock Code and Year. In source data you have no combination Stock Code=FXL and Year=1, however in answers you suggest 5% for Year=2. Why?
If ignore above formula could be
=IFERROR(
INDEX($C$12:$S$15,
MATCH(1,INDEX(($C$12:$C$15=C$4)*($D$12:$D$15=$C$3),0),0),
MATCH(TRUE,ISNUMBER(SEARCH($C$2,$C$10:$S$10)),0)),
"N/A")
Couple of more comments. Your file is practically not downloadable, perhaps due to comma in name - not all system support it.
I'd recommend not to use Merging Cells. Potentially you will have lot of issues continue using merging. Alternative is - select sequential horizontal cells and apply Center Across Selection
HIiSergeiBaklan
Thanks for your help.
From the formula i notice it looks at case, scenario, year. I will columns for min, median, max and sd for each of these. Can this criteria be added to the formula?
Kind regards,
- SergeiBaklanJul 01, 2019Diamond Contributor
To simplify the things you may define constants in Formulas->Name Manager as
when formula for the median is modified as
=IFERROR(INDEX($C$12:$T$15, MATCH(1,INDEX(($C$12:$C$15=C$4)*($D$12:$D$15=$C$3),0),0), MATCH(TRUE,ISNUMBER(SEARCH($C$2,$C$10:$T$10)),0)+ShiftMedian), "N/A")Sure you may use simply +0 or +1 or +2 or +3 in that part of formula.
- calof1Jul 02, 2019Iron Contributor
Hi SergeiSergeiBaklan
Thank you kindly again for your assistance. I am learning a lot, very much appreciated.
Kind regards,
- SergeiBaklanJul 02, 2019Diamond Contributor
calof1 , you are welcome