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martin77's avatar
martin77
Copper Contributor
Apr 16, 2019
Solved

Formula to identify the time closest to 07:00

Hi,   I would like to be able to identify which cells have the time which is closest to 07:00 on any given day.  Does anyone know how this might be done?   Please see the attached image to illust...
excel
Formulas and Functions
  • SergeiBaklan's avatar
    SergeiBaklan
    Apr 16, 2019

    martin77 , for such sample

    it could be

    =A2=IF(INT(A2)+7/24-AGGREGATE(14,6,1/(INT(A2)+7/24>$A$2:$A$26)*$A$2:$A$26,1)<
       AGGREGATE(15,6,1/(INT(A2)+7/24<=$A$2:$A$26)*$A$2:$A$26,1)-(INT(A2)+7/24),
                     AGGREGATE(14,6,1/(INT(A2)+7/24>$A$2:$A$26)*$A$2:$A$26,1),
                     AGGREGATE(15,6,1/(INT(A2)+7/24<=$A$2:$A$26)*$A$2:$A$26,1))
JKPieterse's avatar
JKPieterse
Silver Contributor
Apr 16, 2019
You could try a conditional format, custom function like this:
=AND(HOUR(A2)>6,HOUR(A2)<8)
It would highlight any row with a time in column A between 6 and 8
martin77's avatar
martin77
Copper Contributor
Apr 16, 2019

Many thanks JKPieterse,for the feedback, unfortunately that will not help because if the datetime range were different, it is possible that the times could be before 06:00 or after 08:00.

 

Here is another example to show you what I mean:

 

 

 

  • SergeiBaklan's avatar
    SergeiBaklan
    Diamond Contributor
    Apr 16, 2019

    martin77 , for such sample

    it could be

    =A2=IF(INT(A2)+7/24-AGGREGATE(14,6,1/(INT(A2)+7/24>$A$2:$A$26)*$A$2:$A$26,1)<
       AGGREGATE(15,6,1/(INT(A2)+7/24<=$A$2:$A$26)*$A$2:$A$26,1)-(INT(A2)+7/24),
                     AGGREGATE(14,6,1/(INT(A2)+7/24>$A$2:$A$26)*$A$2:$A$26,1),
                     AGGREGATE(15,6,1/(INT(A2)+7/24<=$A$2:$A$26)*$A$2:$A$26,1))
    • martin77's avatar
      martin77
      Copper Contributor
      Apr 16, 2019

      WowSergeiBaklan - That is amazing.  :-)

       

      Thanks you so much for your help.  I am now going to investigate what you have done here as I am not yet familiar with the 'aggregate' formula.

       

       

      • SergeiBaklan's avatar
        SergeiBaklan
        Diamond Contributor
        Apr 16, 2019

        martin77 ,

         

        Hi Martin,

         

        AGGREGATE finds largest (first parameter 14) or smallest (15) value in the array (third parameter) ignoring all errors (second parameter = 6). Array is multiplication of 1/(...), which gives ignored error if time is more than/less than 7am for given date, on dates itself. Thus first part gives error or 1, multiplied on the date it returns error or date.

        Finding closest early time and closest later time we compare it, and depends on where the difference is less take one or another.

         

        What I forgot that's to test if you have exactly 7:00 in your date/time, perhaps we shall use <= (or >=) in one of conditions instead of < or > (AGGREGATE will return exact date in both cases)

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