Forum Discussion
Finding For Specific Orders
=UNIQUE(FILTER('2022 Jan-Oct Data'!A:A,COUNTIFS('2022 Jan-Oct Data'!A:A,'2022 Jan-Oct Data'!A:A,'2022 Jan-Oct Data'!$AA:$AA,"<>"&"LOF")=0))
In your formula you refer to "LOF". According to your example you want "LOP".
Your formula refers to the whole columns A:A and AA:AA in sheet 2022 Jan-Oct Data. This is a reference to over 1 million rows and might result in an excessively long calculation time. Therefore i'd suggest to refer to e.g. 70000 rows if your data is over 50000 rows.
The 0 result means that there are 0 receipt numbers which only have code LOF. I applied this formula to a sample worksheet and it returned the expected result:
=UNIQUE(FILTER('2022 Jan-Oct Data'!A1:A70000;COUNTIFS('2022 Jan-Oct Data'!A1:A70000;'2022 Jan-Oct Data'!A1:A70000;'2022 Jan-Oct Data'!AA1:AA70000;"<>"&"LOP")=0))
As you can see here there are duplicate entries with different codes 20p, unknown and LOP and so on. I want to find the entries on the left that only has LOP and nothing else. if the entry has something other than an LOP I don't want it filtered. if an entry have an LOP and 20P and Unknown i do not want it filtered.. if the entry has only LOP i want to find that entry.. Does that help?
=UNIQUE(FILTER(A2:A19,COUNTIFS(A2:A19,A2:A19,$B$2:$B$19,"<>"&"LOP")=0))You can apply this formula.
when i plugged the formula into the cell it returned Zero, this is the formula i used
=UNIQUE(FILTER('2022 Jan-Oct Data'!A:A,COUNTIFS('2022 Jan-Oct Data'!A:A,'2022 Jan-Oct Data'!A:A,'2022 Jan-Oct Data'!$AA:$AA,"<>"&"LOF")=0))Am i doing something wrong i have over 50,000 rows?