Count how many pairs of dice sum >= 7?

Absolutely. REDUCE can be used to iterate through the number of dice, adding the SEQUENCE of sides (vertical vector) to the previous transposed results using TOROW (horizontal vector). The lambda definition could be something like this:

=LAMBDA(num_of_sides,num_of_dice,operator,value,
    LET(
        n, SEQUENCE(num_of_sides),
        m, IF(num_of_dice = 1, n, REDUCE(n, SEQUENCE(num_of_dice - 1), LAMBDA(a,i, TOROW(a) + n))),
        t, CHOOSE(
            XMATCH(operator, {"<";"<=";"<>";"=";">";">="}),
            m < value, m <= value, m <> value, m = value, m > value, m >= value
        ),
        SUM(--t)/COUNTA(t)
    )
)

You could name it DICEPROBλ, for example, then use it as follows:

=DICEPROBλ(6,2,">=",7)

Or:

=DICEPROBλ(6,3,">",9)

Or:

=DICEPROBλ(6,7,"<",25)

And so on and so forth.

This function returns the probability. If you want it to return the count instead, simply remove /COUNTA(t) from the last line of the function definition.

Note: the PERMλ function was a generic permutation generator I had saved from a previous project. It works but is not the most efficient method for this scenario. Thanks for prompting me to rethink it! 😉