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Peter_Browning's avatar
Peter_Browning
Copper Contributor
Nov 24, 2023

Help with Formula

I have a set of data like this:

 

Reference     Code               Type

12502           FR19511107    Salary

12502           FR19511101    NI Conts

12502           FR19511161    Call Out

12502           FR19511101    Pension

11302           FR19511107    Salary

11302           FR19511101    NI Conts

11302           FR19511161    Overtime

11302           FR19511101    Pension

 

What I want is to add a new column using a formula where I show the Code for showing for salary for each Reference if the Code ends in 1101 or Type = "Salary"

 

Here's what I would want returned for this set of data:

Reference     Code               Type        New Code

12502           FR19511107    Salary      FR19511107

12502           FR19511101    NI Conts  FR19511107

12502           FR19511161    Call Out   FR19511161

12502           FR19511101    Pension    FR19511107

11302           FR19611109    Salary       FR19611109

11302           FR19611101    NI Conts   FR19611109

11302           FR19611161    Overtime  FR19611161   

11302           FR19611101    Pension    FR19611109   

 

Any suggestions as to how this could be done?

  • Peter_Browning 

    =IF(OR(RIGHT(B2,4)="1101",C2="Salary"),INDEX($B$2:$B$9,MATCH(1,($A$2:$A$9=A2)*($C$2:$C$9="Salary"),0)),B2)

     

    You can try this formula. Enter the formula with ctrl+shift+enter if you don't work with Office 365 or Excel for the web or Excel 2021.

    • Peter_Browning's avatar
      Peter_Browning
      Copper Contributor

      OliverScheurich 

      Thank you so much for your help with this.

       

      I have used this formula and it looked like it had worked. I copied the formula down to include all the rows (2170) and it seemed to stop working further down the rows. I copied out a sample for one person and the results of the formula:

       

      The column R shows the results when the data was included in the full listing. The Column U is when I tried applying the formula to the data independently in this cut of it.

       

      Here's the formula for the first row above used in the main data:

      =IF(OR(RIGHT(C106,4)="1101",G106="Salary"),INDEX($C$1:$C$2170,MATCH(1,($B$1:$B$2170=B106)*($G$1:$G$2170="Salary"),0)),C106)

       

      Here's the formula used in Column U above:

      =IF(OR(RIGHT(C1,4)="1101",G1="Salary"),INDEX($C$1:$C$9,MATCH(1,($B$1:$B$9=B1)*($G$1:$G$9="Salary"),0)),C1)

       

      I'm not sure why there's a difference.

      • OliverScheurich's avatar
        OliverScheurich
        Gold Contributor

        Peter_Browning 

        You are welcome. The formula in column R refers to 2170 rows and the formula in column U refers to 9 rows. The screenshot shows 9 rows therefore it's impossible to tell why there are different results. I could only guess why the results are different. Can you attach your file without sensitive data so we can have a look at this?

         
         
  • djclements's avatar
    djclements
    Bronze Contributor

    Peter_Browning It looks like there's a typo in either your sample data or the expected results that could use some clarification. Regarding reference 11302, type "Salary", you're showing code "FR19511107" in the top table, but "FR19611109" in the expected results table. I'm assuming the typo is in the top table, which should be "FR19611109". If so, another option you could use is the FILTER function, if it's available in your version of Excel. For example:

     

    =IF(RIGHT(B2, 4)="1101", FILTER($B$2:$B$9, ($A$2:$A$9=A2)*($C$2:$C$9="Salary"), B2), B2)

     

    The only logical_test needed for the IF function in this situation is to check if the right four characters of the code are equal to "1101". It's not necessary to also check if the type is equal to "Salary" because, if true, it would just find and return its own code anyways.

     

    The FILTER function has an optional [if_empty] parameter, which can be used to return the original code if no corresponding "Salary" record is found. If that's not even a possibility with your data, though, you can safely exclude that argument. Cheers!

  • steve_luke's avatar
    steve_luke
    Copper Contributor

    Peter_Browning Can you assist me in creating a formula that works

     

    I want to enter a name in one cell.  Once the name is added then the amount owed to auto populate the amount owing into another cell.  When I change the name, the amount moves to the owing cell.  This sound stupid.  I hope my picture helps.

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

     

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