Excel formula help

[AttilaHetey]

Hey, 

I have the following table. 

A	B	C	D	E	F	G	H	I	J	K	L	M	N
IP Address	CIDR	Netmask	Start IP	End IP	Broadcast IP	# of Hosts	1st OCT	2st OCT	3st OCT	IP Start	IP End	Country	Type
							1	2	3	4	4
10.16.215.0	24	255.255.255.0	10.16.215.1	10.16.215.254	10.16.215.255	254	10	16	215	1	254	HU	Server
10.17.215.0	24	255.255.255.0	10.17.215.1	10.17.215.254	10.17.215.255	254	10	17	215	1	254	AT	Image Device
10.10.170.23	28	255.255.255.240	10.10.170.17	10.10.170.30	10.10.170.31	14	10	10	170	17	30	SI	IOT
10.11.1.0	24	255.255.255.0	10.11.1.1	10.11.1.254	10.11.1.255	254	10	11	1	1	254	CRO	External Managed Devices
10.10.32.0	27	255.255.255.224	10.10.32.1	10.10.32.30	10.10.32.31	30	10	10	32	1	30	HU	Maxnet card readers
10.10.32.64	26	255.255.255.192	10.10.32.65	10.10.32.126	10.10.32.127	62	10	10	32	65	126	HU	Whatever

These are IP adressess (in A) and i have already broken them down into ranges - column K and L 

In a seperate field i want to compare the values in this table column H-L with an IP address (4 seperate columns e.g. 10.16.215.2 to 4 columns 10 16 215 2) and find the exact row where the IP addrss is matching.

In other words - I want to create a search field where someone puts an IP address - it is then converted into 4 columns for the octets (i know how to do that) and then compared/matched with the 4 numbers in the table from column H-L by also making sure that the 4th searched number is within the range of K-L. I want to return Column M and N as a result. 

My goal is a searchable database where one can put in an IP and immadietely sees the country and the type/description without manually going through the list. 

I have tried 

=IF(AND(U15>=$K3, U15<=L3), IF(COUNTIF(H2:H6,R15)+COUNTIF(I2:I6,S15)+COUNTIF(J2:J6,T15)>=3, "Match", "Not Match"), "Not Match")

But this is not really the solution as it does not search in the whole column and it just returns Match or NO Match. Also tried with Vlookup but i am lost at this point.

Any help is appriciated, i am not great with functions in general unfortunately. 

Thanks a lot

[#2]

@AttilaHetey 

Will the CIDR never be less than 24? It it were less than 24, the first three octets of the end IP could be different from that of the start IP.

[#3 · Accepted solution]

@AttilaHetey 

On Excel 365, and if I understood the logic correctly, that could be

=XLOOKUP(
 1,
 (TEXTBEFORE($A12,".",3) = TEXTBEFORE($D$3:$D$8,".",3)) *
 (--TEXTAFTER($A12,".",3) >= --TEXTAFTER($D$3:$D$8,".",3)) *
 (--TEXTAFTER($A12,".",3) <= --TEXTAFTER($E$3:$E$8,".",3)),
 $N$3:$N$8,
 "no such" )

[#4]

Man, this is perfect, thank you soo much. I thought that Excel cannnot comprehend IP ranges that is why i have broken it down to octets so i can make calculations with the last octet (that is a range) but your XLOOKUP somehow just works. I owe you a beer.

[#5]

Sergei have answered with a working code, but thank you also for looking into this mate.

[#6]

There is something wrong though.

If i search 10.11.185.184
It cannot find this in the range of
IP CIDR Netmask Start IP End IP
10.11.185.0 16 255.255.0.0 10.11.0.1 10.11.255.254


Do you know why this is the case? i see this with every 16 CIDR while it should be within the range.

[#7]

@AttilaHetey 

Sorry, my logic was wrong, assumed first 3 octets are the same.

Taking into account that you already have Start IP and End IP formula could be

=LET(
startIP,   $D$3:$D$9, endIP, $E$3:$E$9, type, $N$3:$N$9, ip, $A12,
decimallP, LAMBDA(v, SUM(TEXTSPLIT(v, ".")*256^{3,2,1,0}) ),
afterStart,BYROW( startIP, LAMBDA(v, decimallP(ip) >= decimallP(v)  ) ),
beforeEnd, BYROW( endIP, LAMBDA(v, decimallP(ip) <= decimallP(v) ) ),
XLOOKUP(1, afterStart*beforeEnd, type,"no such")
)

In it every IP address is converted into decimal form and we compare them not care about octets.

Didn't play with that, in general we may include into above formula calculation of Start/End IP as well using CIDR.

[#8]

Thanks a lot man, this now works like a charm. I tested it and i think its fine now. Mind that i have over 7k IP ranges and will probably increase.
Thanks again

[#9]

@AttilaHetey , you are welcome, glad to help