Sep 17 2023 10:38 PM
Hi
I have a spreadsheet with 2 sheets.....Sheet A (data) and Sheet B (input). I have created a table in A and managed to create a data entry form. In sheet B I created a button and attached a macro which opens A and the data entry form.
The first problem I have is that whenever I try to enter data I get "Cannot extend table or database".
Now this is my wishlist...please note that I am not fluent in VBA etc.
1. Can I create a data entry form that is always displayed in B to enable creation of new data and searching?
2. How do I get rid of the error I am currently getting?
I was hoping to attach a sample but can't see where to do that.
Many thanks
Debbie
Sep 17 2023 10:48 PM
It seems like you are trying to create a data entry form in Excel 365 that allows you to input data into a table and perform searches. To address your questions:
Step 1: Create a UserForm
Step 2: Code the UserForm
Next, you will need to write VBA code to handle interactions with the UserForm. For example, you will write code to add data to your table when the user clicks a "Submit" button.
Here is a simple example of VBA code to add data to a table:
vba code:
Private Sub SubmitButton_Click()
Dim ws As Worksheet
Dim tbl As ListObject
Dim newRow As ListRow
' Set the worksheet and table
Set ws = ThisWorkbook.Sheets("SheetA")
Set tbl = ws.ListObjects("TableName") ' Replace "TableName" with your table name
' Add a new row to the table
Set newRow = tbl.ListRows.Add(AlwaysInsert:=True)
' Fill in data from UserForm controls
newRow.Range(1, 1).Value = TextBox1.Value ' Replace with your control names and values
' Close the UserForm
Unload Me
End Sub
Step 3: Show the UserForm
You can add a button to Sheet B and attach code to display the UserForm when clicked. Here's a simplified example:
vba code:
Private Sub ShowFormButton_Click()
UserForm1.Show ' Replace "UserForm1" with your UserForm's name
End Sub
The "Cannot extend table or database" error typically occurs when you are trying to add data to a table, and Excel is unable to determine the table's size correctly. You can try the following steps to resolve this issue:
By creating a UserForm for data entry in Sheet B and handling data submission through VBA code, you can achieve your goal of entering and managing data more effectively. The text, steps and codes were created with the help of AI.
My answers are voluntary and without guarantee!
Hope this will help you.
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Sep 18 2023 12:15 AM
Thanks so much....I am amazed that I have got this far so far....still a way to go.
I have created the user form:
I tried applying the code to 'submit' and 'new entry' as you can see i have a problem with the latter.
I appreciate your patience (this is all new to me) but what have i done wrong to get the error and how do i test the user form.
I am not sure how to open the excel spreadsheet with the user form displayed.
Code for the 'search' would be great
Aug 13 2024 09:41 AM - edited Aug 13 2024 09:42 AM
can you look through this code i am having issues with the form section
Option Compare Database Option Explicit ' Main entry point for setting up the Special Education Database Public Sub SetupSpecialEdDatabase() On Error GoTo ErrorHandler Dim db As DAO.Database Set db = CurrentDb ' Step 1: Create database structure CreateDatabaseStructure db AddControlToForm MsgBox "Special Education Database setup completed successfully!", vbInformation Exit Sub ErrorHandler: MsgBox "An error occurred: " & Err.Description, vbCritical End Sub ' Function to check if a table exists Private Function TableExists(db As DAO.Database, tableName As String) As Boolean Dim td As DAO.TableDef For Each td In db.TableDefs If td.Name = tableName Then TableExists = True Exit Function End If Next td TableExists = False End Function ' Subroutine to create the database structure Private Sub CreateDatabaseStructure(db As DAO.Database) CreateStudentsTable db CreateStaffTable db CreateServicesTable db CreateStudentServicesTable db CreateProgressReportsTable db CreateRelationships db End Sub ' Subroutines to create individual tables Private Sub CreateStudentsTable(db As DAO.Database) If Not TableExists(db, "Students") Then Dim tdf As DAO.TableDef Set tdf = db.CreateTableDef("Students") With tdf .Fields.Append .CreateField("StudentID", dbLong) .Fields("StudentID").Attributes = dbAutoIncrField .Fields.Append .CreateField("FirstName", dbText, 50) .Fields.Append .CreateField("LastName", dbText, 50) .Fields.Append .CreateField("DateOfBirth", dbDate) .Fields.Append .CreateField("Gender", dbText, 1) .Fields.Append .CreateField("GuardianName", dbText, 100) .Fields.Append .CreateField("GuardianContact", dbText, 20) .Fields.Append .CreateField("Address", dbText, 200) .Fields.Append .CreateField("EnrollmentDate", dbDate) .Fields.Append .CreateField("Grade", dbInteger) .Fields.Append .CreateField("PrimaryDiagnosis", dbText, 100) .Fields.Append .CreateField("SecondaryDiagnosis", dbText, 100) .Fields.Append .CreateField("IEPDate", dbDate) End With db.TableDefs.Append tdf Dim idx As DAO.Index Set idx = tdf.CreateIndex("PrimaryKey") idx.Fields.Append idx.CreateField("StudentID") idx.Primary = True tdf.Indexes.Append idx End If End Sub Private Sub CreateStaffTable(db As DAO.Database) If Not TableExists(db, "Staff") Then Dim tdf As DAO.TableDef Set tdf = db.CreateTableDef("Staff") With tdf .Fields.Append .CreateField("StaffID", dbLong) .Fields("StaffID").Attributes = dbAutoIncrField .Fields.Append .CreateField("FirstName", dbText, 50) .Fields.Append .CreateField("LastName", dbText, 50) .Fields.Append .CreateField("Role", dbText, 50) .Fields.Append .CreateField("Specialization", dbText, 100) .Fields.Append .CreateField("Email", dbText, 100) .Fields.Append .CreateField("Phone", dbText, 20) End With db.TableDefs.Append tdf Dim idx As DAO.Index Set idx = tdf.CreateIndex("PrimaryKey") idx.Fields.Append idx.CreateField("StaffID") idx.Primary = True tdf.Indexes.Append idx End If End Sub Private Sub CreateServicesTable(db As DAO.Database) If Not TableExists(db, "Services") Then Dim tdf As DAO.TableDef Set tdf = db.CreateTableDef("Services") With tdf .Fields.Append .CreateField("ServiceID", dbLong) .Fields("ServiceID").Attributes = dbAutoIncrField .Fields.Append .CreateField("ServiceName", dbText, 100) .Fields.Append .CreateField("Description", dbMemo) End With db.TableDefs.Append tdf Dim idx As DAO.Index Set idx = tdf.CreateIndex("PrimaryKey") idx.Fields.Append idx.CreateField("ServiceID") idx.Primary = True tdf.Indexes.Append idx End If End Sub Private Sub CreateStudentServicesTable(db As DAO.Database) If Not TableExists(db, "StudentServices") Then Dim tdf As DAO.TableDef Set tdf = db.CreateTableDef("StudentServices") With tdf .Fields.Append .CreateField("StudentServiceID", dbLong) .Fields("StudentServiceID").Attributes = dbAutoIncrField .Fields.Append .CreateField("StudentID", dbLong) .Fields.Append .CreateField("ServiceID", dbLong) .Fields.Append .CreateField("StaffID", dbLong) .Fields.Append .CreateField("StartDate", dbDate) .Fields.Append .CreateField("EndDate", dbDate) .Fields.Append .CreateField("Frequency", dbText, 50) .Fields.Append .CreateField("Goals", dbMemo) End With db.TableDefs.Append tdf Dim idx As DAO.Index Set idx = tdf.CreateIndex("PrimaryKey") idx.Fields.Append idx.CreateField("StudentServiceID") idx.Primary = True tdf.Indexes.Append idx End If End Sub Private Sub CreateProgressReportsTable(db As DAO.Database) If Not TableExists(db, "ProgressReports") Then Dim tdf As DAO.TableDef Set tdf = db.CreateTableDef("ProgressReports") With tdf .Fields.Append .CreateField("ReportID", dbLong) .Fields("ReportID").Attributes = dbAutoIncrField .Fields.Append .CreateField("StudentID", dbLong) .Fields.Append .CreateField("ReportDate", dbDate) .Fields.Append .CreateField("AcademicProgress", dbMemo) .Fields.Append .CreateField("BehavioralProgress", dbMemo) .Fields.Append .CreateField("SocialProgress", dbMemo) .Fields.Append .CreateField("NextSteps", dbMemo) End With db.TableDefs.Append tdf Dim idx As DAO.Index Set idx = tdf.CreateIndex("PrimaryKey") idx.Fields.Append idx.CreateField("ReportID") idx.Primary = True tdf.Indexes.Append idx End If End Sub Private Sub CreateRelationships(db As DAO.Database) On Error Resume Next ' In case relationships already exist Dim rel As DAO.Relation Set rel = db.CreateRelation("StudentsStudentServices", "Students", "StudentServices", dbRelationUpdateCascade) rel.Fields.Append rel.CreateField("StudentID") rel.Fields("StudentID").ForeignName = "StudentID" db.Relations.Append rel Set rel = db.CreateRelation("ServicesStudentServices", "Services", "StudentServices", dbRelationUpdateCascade) rel.Fields.Append rel.CreateField("ServiceID") rel.Fields("ServiceID").ForeignName = "ServiceID" db.Relations.Append rel Set rel = db.CreateRelation("StaffStudentServices", "Staff", "StudentServices", dbRelationUpdateCascade) rel.Fields.Append rel.CreateField("StaffID") rel.Fields("StaffID").ForeignName = "StaffID" db.Relations.Append rel Set rel = db.CreateRelation("StudentsProgressReports", "Students", "ProgressReports", dbRelationUpdateCascade) rel.Fields.Append rel.CreateField("StudentID") rel.Fields("StudentID").ForeignName = "StudentID" db.Relations.Append rel On Error GoTo 0 ' Reset error handling End Sub Private Sub CreateStudentEntryForm() On Error GoTo ErrorHandler Dim db As DAO.Database Dim strFormName As String Dim frm As Form Set db = CurrentDb strFormName = "frmStudentEntry" ' Check if the form already exists If DCount("*", "MSysObjects", "Type=(-32768) AND Name='" & strFormName & "'") > 0 Then MsgBox "The Student Entry form already exists.", vbInformation Exit Sub End If ' Create a new form Set frm = Application.CreateForm ' Set form properties With frm .Name = strFormName .RecordSource = "Students" .Caption = "Student Entry Form" ' Add controls to the form AddControlToForm .Name, acTextBox, "StudentID", "Student ID:", 1000, 400 AddControlToForm .Name, acTextBox, "FirstName", "First Name:", 1000, 800 AddControlToForm .Name, acTextBox, "LastName", "Last Name:", 1000, 1200 AddControlToForm .Name, acTextBox, "DateOfBirth", "Date of Birth:", 1000, 1600 AddControlToForm .Name, acTextBox, "Gender", "Gender:", 1000, 2000 AddControlToForm .Name, acTextBox, "GuardianName", "Guardian Name:", 1000, 2400 AddControlToForm .Name, acTextBox, "GuardianContact", "Guardian Contact:", 1000, 2800 AddControlToForm .Name, acTextBox, "Address", "Address:", 1000, 3200 AddControlToForm .Name, acTextBox, "EnrollmentDate", "Enrollment Date:", 1000, 3600 AddControlToForm .Name, acTextBox, "Grade", "Grade:", 1000, 4000 AddControlToForm .Name, acTextBox, "PrimaryDiagnosis", "Primary Diagnosis:", 1000, 4400 AddControlToForm .Name, acTextBox, "SecondaryDiagnosis", "Secondary Diagnosis:", 1000, 4800 AddControlToForm .Name, acTextBox, "IEPDate", "IEP Date:", 1000, 5200 ' Add navigation buttons AddControlToForm .Name, acCommandButton, "cmdFirst", "First", 1000, 5600, 1000, 400, "=DoCmd.GoToRecord , , acFirst" AddControlToForm .Name, acCommandButton, "cmdPrevious", "Previous", 2100, 5600, 1000, 400, "=DoCmd.GoToRecord , , acPrevious" AddControlToForm .Name, acCommandButton, "cmdNext", "Next", 3200, 5600, 1000, 400, "=DoCmd.GoToRecord , , acNext" AddControlToForm .Name, acCommandButton, "cmdLast", "Last", 4300, 5600, 1000, 400, "=DoCmd.GoToRecord , , acLast" End With ' Save and close the form DoCmd.Close acForm, frm.Name, acSaveYes MsgBox "Student Entry form created successfully!", vbInformation Exit Sub ErrorHandler: MsgBox "An error occurred while creating the form: " & Err.Description, vbCritical End Sub
Aug 13 2024 11:00 PM
Troubleshooting the Special Education Database Setup in Access VBA
Vba Code is untested backup your file.
If DCount("*", "MSysObjects", "Type=(-32768) AND Name='" & strFormName & "'") > 0 Then
MsgBox "The Student Entry form already exists.", vbInformation
Exit Sub
End If
If you want to overwrite the form or create it anew, you might need to delete the existing form first.
Vba Code is untested backup your file first.
Private Sub AddControlToForm(ByVal formName As String, controlType As AcControlType, controlName As String, controlCaption As String, leftPos As Integer, topPos As Integer, Optional width As Integer = 0, Optional height As Integer = 0, Optional controlSource As String = "")
Dim ctrl As Control
Set ctrl = Forms(formName).Controls.Add(controlType, controlName)
With ctrl
.Caption = controlCaption
.Left = leftPos
.Top = topPos
If width > 0 Then .Width = width
If height > 0 Then .Height = height
If controlSource <> "" Then .ControlSource = controlSource
End With
End Sub
3. General Advice:
If the form creation part is causing issues, test the code in smaller chunks. Create a simple form first, adding one control at a time, and see where it fails. This will help you isolate the problem.
I hope these explanations help you with your VBA projects.
Aug 13 2024 11:05 PM
VBA Data Entry Form and Search Functionality in Excel
1. Resolving the "Cannot extend table or database" Error: This error typically occurs when Excel cannot expand the table due to existing data, merged cells, or blank rows/columns surrounding the table. Here’s how to address this issue:
If the problem persists, consider recreating the table to ensure it's correctly defined.
2. Making the UserForm Always Visible on Sheet B: To have a UserForm always available on Sheet B for data entry and searching, follow these steps:
Vba Code is untested backup your file first
Private Sub ShowFormButton_Click()
UserForm1.Show ' Replace "UserForm1" with your UserForm's name
End Sub
Submit Data from the UserForm:
Vba Code is untested backup your file first.
Private Sub SubmitButton_Click()
Dim ws As Worksheet
Dim tbl As ListObject
Dim newRow As ListRow
' Set the worksheet and table
Set ws = ThisWorkbook.Sheets("SheetA")
Set tbl = ws.ListObjects("YourTableName") ' Replace with your table name
' Add a new row to the table
Set newRow = tbl.ListRows.Add(AlwaysInsert:=True)
' Fill in data from UserForm controls
newRow.Range(1, 1).Value = TextBox1.Value ' Adjust control names accordingly
' Close the UserForm
Unload Me
End Sub
3. Adding a Search Functionality: You can also add a search function to the UserForm that allows users to search for existing data. Here’s a simple way to implement it:
Vba Code is untested backup your file first
Private Sub SearchButton_Click()
Dim ws As Worksheet
Dim tbl As ListObject
Dim foundCell As Range
Dim searchValue As String
' Set the worksheet and table
Set ws = ThisWorkbook.Sheets("SheetA")
Set tbl = ws.ListObjects("YourTableName") ' Replace with your table name
' Get the search value from the TextBox
searchValue = SearchBox.Value
' Search in the first column of the table
Set foundCell = tbl.ListColumns(1).DataBodyRange.Find(What:=searchValue, LookIn:=xlValues)
' Display search results
If Not foundCell Is Nothing Then
MsgBox "Found: " & foundCell.Value, vbInformation
Else
MsgBox "No match found.", vbExclamation
End If
End Sub
This simple search will look for a value in the first column of the table and notify the user if a match is found.