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Kaddrik's avatar
Kaddrik
Copper Contributor
Mar 16, 2022
Solved

Count the number of dates based on a condition

Hello,

 

hope you are doing good.

 

I have a pivot table with dates in a column. Using conditional formating i set the dates that are between today and up to 329 away as green , those that between 330 and 365 to be orange and more than 365 as red:

 

green  =AND(TODAY()-$H19>=0,TODAY()-$H19<329)

orange  =AND(TODAY()-$H19>=330,TODAY()-$H19<365)

red  =AND(TODAY()-$H19>=365)

 

since this is conditional formatting i apply that to my whole column H and for all my dates i have some green, some orange and some red...

 

Now i'm trying to count the number or green, orange and red...and that's where i'm stuck... 😞

 

I think i understand i have to use a COUNTIF and i wrote :  =COUNTIF(H:H,"<=" & TODAY()-329) ...this gives me 67   so it's... 67 dates that are smaller than 329 date ago ...if i'm not mistaken, but i don't understand how to have the correct count for each color.

 

Would someone please be able to help me on this ?

 

Thanks in advance

  • Kaddrik 

    Green:

    =COUNTIFS(H:H,">"&TODAY()-329,H:H,"<="&TODAY())

    Orange:

    =COUNTIFS(H:H,">"&TODAY()-365,H:H,"<="&TODAY()-330)

    Red:

    =COUNTIFS(H:H,">0",H:H,"<="&TODAY()-365)

3 Replies

  • Kaddrik 

    Green:

    =COUNTIFS(H:H,">"&TODAY()-329,H:H,"<="&TODAY())

    Orange:

    =COUNTIFS(H:H,">"&TODAY()-365,H:H,"<="&TODAY()-330)

    Red:

    =COUNTIFS(H:H,">0",H:H,"<="&TODAY()-365)

    • Kaddrik's avatar
      Kaddrik
      Copper Contributor
      Hello HansVogelaar

      Thanks a lot for your reply.

      oooh nice !! it seems to be working... well it takes some additional values those H1 to H18 and some at the end when i filter but i least i get a number that is closer to what i should have.
      I guess i could solve this by adding values to range "H:H".

      I will see but it's already a very good point 🙂

      Thanks a lot !!
      • Kaddrik 

        You could change H:H to the relevant part, for example H19:H100. The formulas will be more efficient too.

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