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reject emails to 2 recipients
Hi,
I want to set a Exchange server rule so that anyone that sends and email to address1 AND address2 in the To: field can be rejected. They should be able to send individually to address1 OR a...
- I'm not sure why you have created 6 rules.
Just to be clear about my idea I will attach a screenshot.
So, for example:
A@contoso.com
B@contoso.com
C@contoso.com
Security groups:
Sec1@contoso.com = a+b
Sec2@contoso.com = a+c
Sec3@contoso.com = b+c
Rules:
1) to: c + any member of sec1
2) to: b + any member of sec2
3) to: a + any member of sec3
I look forward to hearing from you.
Hi Graeme,
I would create a security group hidden from GAL and add one of the addresses you want to block. Then create a transport rule:
Apply this rule if...
1) the message >to box contains this person
2) the message >to box contains a member of this group
Do the following...
Reject the message with an explanation
Hope this helps!
I would create a security group hidden from GAL and add one of the addresses you want to block. Then create a transport rule:
Apply this rule if...
1) the message >to box contains this person
2) the message >to box contains a member of this group
Do the following...
Reject the message with an explanation
Hope this helps!
Hi Ricardo,
Many thanks for this. Good thinking!
There is actually 3 addresses I need to incorporate, so I have made 6 rules as it's unlikely they will send to all 3 helpdesk addresses at once, two addresses happens!
I will let it all replicate and feedback tomorrow.
Many thanks for the help
Regards
- I'm not sure why you have created 6 rules.
Just to be clear about my idea I will attach a screenshot.
So, for example:
A@contoso.com
B@contoso.com
C@contoso.com
Security groups:
Sec1@contoso.com = a+b
Sec2@contoso.com = a+c
Sec3@contoso.com = b+c
Rules:
1) to: c + any member of sec1
2) to: b + any member of sec2
3) to: a + any member of sec3
I look forward to hearing from you.Yes thanks Ricardo. I didn't think to add both other addresses to the group and have done them individually to avoid any AND or OR issues, therefore the 6 rules. But I have now created them as per your last post and it works perfectly.
Just what I required. Many thanks for the help and taking the time to make easily understandable. Very much appreciated