VBA code fails in newest build

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Hi,&nbsp;I have had this line of code in a macro for many years&nbsp;&nbsp;&nbsp;Set ImageToAdd = ActiveSheet.Shapes.AddPicture(ImageURL, True, False, _
Cells(RowToAddImage, ColumnToAddImage).Left + 6, _
Cells(RowToAddImage, ColumnToAddImage).Top + (Cells(RowToAddImage, ColumnToAddImage).Height / 2), -1, -1)&nbsp;&nbsp;&nbsp;where ImageURL is a valid url for an image that is publicly available on the internet.&nbsp;This works as expected in&nbsp;&nbsp;Microsoft® Excel® for Microsoft 365 MSO (Version 2210 Build 16.0.15726.20068) 32-bit &nbsp;But is throwing the following error in version 2210 Build 15726.20174&nbsp;Run-time error 1004. The specified file was not found.&nbsp;Could anyone advise a solution or how I should report this as an issue to MS?&nbsp;Thanks,Richard

nikolinode · Answer

lazuli1485&nbsp;I think this could be because the macro was placed at the worksheet level...without being sure as don't have a full picture of the code/file/intend.&nbsp;Try right-clicking on the module node in the VBA project window,click "Insert" =&gt; "Module"and then paste your macro into the new module(make sure you use the macro recorded at worksheet level Clear).&nbsp;Hope I could help you with these information / links.&nbsp;NikolinoDEI know I don't know anything (Socrates)

lazuli1485 · Answer

NikolinoDE&nbsp;Thank you for the suggestion. Unfortunately not - the line is in a module and always has been.

mtarler · Answer

are you sure RowToAddImage, ColumnToAddImage are both valid and don't have or result in a bad reference

lazuli1485 · Answer

Hi,&nbsp;Both are valid. I've stripped the code back and it can be inserted into a blank workbook to test:&nbsp;Private Sub CommandButton1_Click() 
Dim ImageToAdd 
Dim RowToAddImage 
RowToAddImage = 2
Dim ColumnToAddImage 
ColumnToAddImage = 7   
Dim ImageURL As String
'ImageURL = "https://peters.co.uk/rgw/assets/covers/large/513/9781910002513.jpg" ' fails
ImageURL = "https://peters.co.uk/uploads/downloads/medium/9781910002513.jpg" 'same image, same website, works
Set ImageToAdd = ActiveSheet.Shapes.AddPicture(ImageURL, True, False, _             
Cells(RowToAddImage, ColumnToAddImage).Left + 6, _             
Cells(RowToAddImage, ColumnToAddImage).Top + (Cells(RowToAddImage, ColumnToAddImage).Height / 2), -1, -1) 
End Sub &nbsp;As you can see I've narrowed the error down - it is conditional upon the image source. It will work with an image hosted on Google or Amazon. It works with the image stored in one valid web location, but will not work in another.&nbsp;My assumption at this point is that the newer builds is not treating the fail location as secure... but I have no idea why this might be the case.&nbsp;

mtarler · Answer

Not much more help but a few things I checked:the files are the exact same but if i download both either will work from local driveI got same results using ActiveSheet.Pictures.Insert(ImageURL)i wonder if there is any issue with server location in that the one that doesn't work appears to be inside someone's account (https://peters.co.uk/rgw/assets/...) as opposed to the other that appears to be a public location (https://peters.co.uk/uploads/...). I know both can be viewed in a browser without any log in but maybe the site permissions for those location are different. I wonder if this has anything to do with the cross-origin sharing standard (CORS).

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VBA code fails in newest build

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