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Text Filter
Hello All,
Would you be able to tell me how to filter two columns of individual names for differences, that rule out middle initials?
I've tried using a filter that would tell me if the names were essentially the same but I received "false" results including names that were only differentiated due to a middle initial...
Any suggestions?
18 Replies
- SergeiBaklanDiamond Contributor
Sample is in Sheet3 attached, but I'm missed with the logic:
- Are names always as LastName FirstName <MiddleName or Initial> where the latest is optional? Or that could be like LastName <MiddleName> FirstName?
- Names as "Calendar Amy L" and "Calendar Amy Lynn" are considered as the same. But what about "Calendar Amy J" or whatever is on the third position - is that the same "Calendar Amy"?
- AsiaYCopper ContributorYes, all names are listed last name first name middle initial suffix (if any) ...
If the middle initial is different then yes it is a different person...
I really appreciate your help ... let me know what you think.- SergeiBaklanDiamond Contributor
One more question - if no initial / middle name this person consider as different to one who has no such? For example
1) Calendar Amy
2) Calendar Amy L
3) Calendar Amy Lynn
4) Calendar Amy H
2) and 3) are the same. 4) is different from 2) and 3). What about 1), is it different from all of them or it's the same as 2),3) or same as 4) and if two latest options how we shall know which one to take.
- SergeiBaklanDiamond Contributor
For the collection, Power Query variant
by
let Source = Excel.CurrentWorkbook(){[Name="Names"]}[Content], RemoveMiddle = Table.AddColumn(Source, "Different Names", each let splitNames = Splitter.SplitTextByDelimiter(" ", QuoteStyle.None)([Names]) in Text.Combine({splitNames{0}, " ", List.Last(splitNames)}), type text), RemoveDuplicates = Table.Distinct(RemoveMiddle, {"Different Names"}), RemoveSource = Table.SelectColumns(RemoveDuplicates,{"Different Names"}) in RemoveSourceActually no coding is required, script is generated by Column By Example.
- AsiaYCopper Contributor
Hello Sergei,
Your example is great except I am needing to only find names that are different in two columns of names, where each name is listed side by side but could be listed different as Calendar Amy L or Calendar Amy Lynn …
Any suggestions?
- PeterBartholomew1Silver Contributor
I think you are correct in that PQ is the way to go with data analysis problems. In particular I welcome the degree of structure offered by Tables and PQ that is missing from normal spreadsheet usage.
Now though, DAs have hugely improved the usability of arrays for model building. What is confusing is that the new DA functions also provide an alternative approach for data analysis steps (sorting, filtering etc).
There is now a big area of overlap where either methodology is viable. I am not certain where the borderlines are in terms of which option should be recommended for what problems. At the moment, it is a case of trying each and determining on a case-by-case basis which works out the better.
- PeterBartholomew1Silver Contributor
Just to demonstrate that my post above wasn't merely the product of a deranged mind, I attach a functioning workbook (standard installation rather than insider). The name 'testName' is now a relative reference to a cell in the column header and the sequence 'k' is now somewhat more turgid
k: =COLUMN( INDEX(aRow,1):INDEX(aRow,n))
[not that a number sequence should rely upon the definition of a somewhat arbitrary range]
- PeterBartholomew1Silver Contributor
Warning: This is an experiment testing formulas using modern Dynamic Arrays.
n: = LEN(@testName); select a name from the column headers and determine its length
k: = SEQUENCE(1,n); define a sequence counter for characters
chr: = MID( @testName, k, 1 ); split the test name into separate characters
firstName: = LEFT( @testName, MIN( IF( chr=" ", k ) ) ); extract first name
lastName: = RIGHT( @testName, n - MAX(IF( chr=" ", k ) ) ); extract last name
Worksheet formula:
= ( LEFT(fullName, LEN(firstName)) = firstName) *
(RIGHT(fullName, LEN(lastName)) = lastName);
compares an array of full names against the test name.
Tom B. Jones James A Smith Tom H Jones 1 0 James B. Jones 0 0 Tom B Jones 1 0 Chris Williams 0 0 James Smith 0 1 James X. L. Smith 0 1 - AsiaYCopper Contributor
Hi Peter,
Is there a way to extract the data without having to use test names? Each name in the two columns that I have are listed without any commas or other special characters as last name first name middle name/initial...
Hoping to find a way to rule out same names that have a middle name/initial listed...
For example, Hampton Sally E shows false to Hampton Sally Egg...
Any thoughts?
- Haytham AmairahSilver Contributor
Hi,
Please try this formula to compare two names regardless of the middle initial:
=TRIM(LEFT(A1,FIND(" ",LOWER(A1),1))) & " " & TRIM(MID(A1,FIND(" ",LOWER(A1),FIND(" ",LOWER(A1),1)+1)+1,LEN(A1)-FIND(" ",LOWER(A1),1)+1))=TRIM(LEFT(B1,FIND(" ",LOWER(B1),1))) & " " & TRIM(MID(B1,FIND(" ",LOWER(B1),FIND(" ",LOWER(B1),1)+1)+1,LEN(B1)-FIND(" ",LOWER(B1),1)+1))The formula is found in this https://www.extendoffice.com/documents/excel/1779-excel-remove-middle-initial.html, I've applied it on two cells and compare them in terms of equality using = sign.
Regards
- AsiaYCopper Contributor
Is there a way to tweak the formula to list names as last, first, middle initial? The formula works except it still shows false for names listed not exactly the same... for example Jones Santa C is false to Jones Santa...
- Haytham AmairahSilver Contributor
It seems difficult to add this odd case to the formula, so I suggest to separate the names that have the initial in the last in a separate sheet and compare them using the below formula.
Or alternatively, you can add it in the next column next to the previous formula as a second check.
=IF(LEN(TRIM(A1))-LEN(TRIM(SUBSTITUTE(A1," ","")))+1=3,TRIM(SUBSTITUTE(A1,MID(A1,LEN(A1)-1,2),"")),A1)=IF(LEN(TRIM(B1))-LEN(TRIM(SUBSTITUTE(B1," ","")))+1=3,TRIM(SUBSTITUTE(B1,MID(B1,LEN(B1)-1,2),"")),B1)
Hope that helps
- AsiaYCopper Contributor