Forum Discussion
Material Leftovers
sg2021 Since the Max and the Max/Rot are the same you know a solution is with all them in same direction. The product L x 3 = 145.5 which is < 156 and then the product W x 13 = 45.5 is < 47 so you can get a grid of 3 x 13 (39) product out of that material all in the same direction.
BTW I wanted to mention that my solution is not the optimized solution in all cases. It will catch some cases that Riny's orig solution didn't but not all. For example if you have a square piece 48"x48" (1/2 sheet of plywood) and you want product that is 23"x25" (not counting loss from cuts) then the original equation would say 2, my improved version 3, but you could get 4 if you cut each piece from a corner of the material and rotate 90deg each time.
I figured out the #value issue, but now have another request that needs to be added into this formula.
How do I add a .03" blade cut for each value? For example, original piece would be 19x36 and need a piece that is 13x16 with a .03" adder for the cut itself?
sg2021 as mathetes said, the easiest way is to add it to the product size dimensions and an easy way to do that is using the NAMES defined by Riny_van_Eekelen . So in the Name Manager just add 0.03 to them there.
Out of curiosity, what was that #Value issue you were having and how did you solve it?
I tried to attach the file but it is just getting stuck when I try. But you can see what I did in the image above.
- That's a tricky one: the most reliable way or simplest way to account for it is to add .06" to each dimension of the sizes of the desired end pieces. I say most reliable, if that level of precision is needed, and you can accept that there might occasionally be one or two fewer end pieces. Otherwise you'd have to somehow incorporate into the calculation how many of the cuts could be made on an outside (not subject to cutting) edge.
So I guess part of this whole project: is the value of the basic material such that it warrants absolute attention to the minimization of the amount of scrap.
Is the material involved such that scrap can be re-worked, melted, smelted, whatever, into new original pieces? If so, you might want to factor in here the cost of re-working material and the cost of precision cutting.
In short, there are (or may be) considerations other than the math we've dealt with so far in just maximizing the number of end pieces that can be cut from a single original piece.
