Forum Discussion
Lookup iferror, index/match errors
Data structure is too complicated. For this one it could be
=IFNA(INDEX(INDEX('Dropdown Lists'!$A$1:$AH$16,0,MATCH([@Position],'Dropdown Lists'!$A$1:$AH$1,0)+2),
MATCH([@Name],INDEX('Dropdown Lists'!$A$1:$AH$16,0,MATCH([@Position],'Dropdown Lists'!$A$1:$AH$1,0)),0),1
),"not found")
Interesting SergeiBaklan! I've never come across the IFNA function before!
Still, see the attached screenshot when I enter the formula. Its returning #NAME? instead. What could I be doing wrong?
- SergeiBaklanSep 21, 2020Diamond Contributor
If you open the file I attached it also returns an error?
- evitajereSep 22, 2020Copper Contributor
NoSergeiBaklan your file doesn't return the same error...you're the real MVP!
I notice at the beginning of your formula, you have ..._xlfn.INFA. What does that do?
Also, the formula is meant to be used in other workbooks reading from the Register. Are you able to help me with creating any dummy workbook that references the Workers Register? I'll be most grateful!
- evitajereSep 22, 2020Copper Contributor
SergeiBaklan. I just read up on the prefix _xlfn:
"Cause. The Excel workbook contains a function that is not supported in the version of Excel that you are currently running. For example, you may have opened a ..."