Forum Discussion

Platinum2000's avatar
Platinum2000
Copper Contributor
Mar 18, 2019
Solved

IF (logical;yes; no) How to use a Date function in the result ?

I need to add a Date function as a result in an IF formula.

 

I tried =IF(R4>0;Date;"") but the result is #¿....  an error. 

 

How I would do it ?

 

Thank you any help

  • DATE must have arguments for YEAR, MONTH, and DAY. For example, your formula might look like this:
    =IF(R4>0,
    DATE(2019,3,18),
    “”)
    The formula returns March 18, 2019, if the value of R4 is more than 0; otherwise, it returns an empty text (“”).

3 Replies

  • Twifoo's avatar
    Twifoo
    Silver Contributor
    DATE must have arguments for YEAR, MONTH, and DAY. For example, your formula might look like this:
    =IF(R4>0,
    DATE(2019,3,18),
    “”)
    The formula returns March 18, 2019, if the value of R4 is more than 0; otherwise, it returns an empty text (“”).
    • Platinum2000's avatar
      Platinum2000
      Copper Contributor
      Thank you Twifoo, it was a bad command I knew, I guessed at beginning maybe this IF command would not accept a funtion in its results, but then I saw a sample, so I thank you very much.
      • Twifoo's avatar
        Twifoo
        Silver Contributor
        In the formula, DATE returns the value_if_true argument of IF. As you will discover, you can use a function to return an argument of another function. Good luck.

Resources