Forum Discussion
How to create a alphanumeric sequence on vba
- Dec 27, 2022
New version:
Function nextUDI(prevUDI As String) As String 'Gera UDI com base no número anterior Dim prefixo As String Dim n As Long Dim prevVal As Long Const strAlphabet = "0123456789ABCDEFGHJKLMNPQRSTUVWXYZ" n = Len(prevUDI) prevVal = 34 * (InStr(strAlphabet, Mid(prevUDI, n - 1, 1)) - 1) + InStr(strAlphabet, Right(prevUDI, 1)) - 1 prefixo = Left(prevUDI, n - 2) nextUDI = prefixo & fBase34(prevVal + 1) End Function
The problem is that the codes must be like the print below.
I try to use the functions below but it didn't work...
Function fBase34(ByRef lngNumToConvert As Long) As String
'Converte base 10 para 34 (base 36 sem I e O)
Dim strAlphabet As String
strAlphabet = "0123456789ABCDEFGHJKLMNPQRSTUVWXYZ"
If lngNumToConvert = 0 Then
Base34Encode = "0"
Exit Function
End If
fBase36Encode = vbNullString
Do While lngNumToConvert <> 0
fBase34 = Mid(strAlphabet, lngNumToConvert Mod 34 + 1, 1) & fBase34
lngNumToConvert = lngNumToConvert \ 34
Loop
If Len(fBase34) = 1 Then
fBase34 = "0" + fBase34
End If
End Function
Function genUDI(ByRef decNum As Long, prefixo As String) As String
'Gera UDI com base em um numero decimal
genUDI = prefixo & fBase34(decNum)
End Function
Function nextUDI(prevUDI As String) As String
'Gera UDI com base no número anterior
prefixo = Left(prevUDI, 5)
nextUDI = prefixo & fBase34(Right(prevUDI, 2) + 1)
End Function
The function genUDI works fine, the problem is the other one...
Function nextUDI(prevUDI As String) As String
'Gera UDI com base no número anterior
Dim prefixo As String
Dim prevVal As Long
prevVal = Application.Decimal(Right(prevUDI, 2), 34)
prefixo = Left(prevUDI, Len(prevUDI) - 2)
nextUDI = prefixo & fBase34(prevVal + 1)
End Function