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mjizy01's avatar
mjizy01
Copper Contributor
Sep 06, 2023
Solved

fomula to use

  • the second column looks like
    =MID(A1,  SEARCH("@",A1)-1,  LEN(A1)-(SEARCH("@",A1)-1) )
    or with Excel 365
    =LET(in,A1:A100, at, SEARCH("@",in)-1, MID(in, at, LEN(in)-at)
    and third column
    =LEFT(A1,SEARCH("@",A1)-1)

6 Replies

      • mtarler's avatar
        mtarler
        Silver Contributor

        the second column looks like
        =MID(A1,  SEARCH("@",A1)-1,  LEN(A1)-(SEARCH("@",A1)-1) )
        or with Excel 365
        =LET(in,A1:A100, at, SEARCH("@",in)-1, MID(in, at, LEN(in)-at)
        and third column
        =LEFT(A1,SEARCH("@",A1)-1)

    • mjizy01's avatar
      mjizy01
      Copper Contributor
      the gmail is the question. i need the fomula that was used to get the results.