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Sajjad_Moslehi's avatar
Sajjad_Moslehi
Copper Contributor
Feb 09, 2020

problem with using MINVERSE function

Hi everybody

I have a problem with using MINVERSE function(I don't have office 365).

When I arrive at the stage in the picture, I press Ctrl+Shift+Enter, but the matrix isn't shown completely and there is only one cell.

What do I have to do?(The second table is selected)

Thank you in advance.

The second table is selected

 

 

 

5 Replies

  • Sajjad_Moslehi 

    Just happened that I had the grid set up for an 8x8 matrix inversion on an open workbook!

     

    I use Office 365 so my inverse matrix spilt correctly and I got agreement with your (1,1) cell.  I then changed the formula to a CSE array.  Did you select the entire 8x8 region, click in the formula bar and commit the formula with Ctrl+Shift+Enter?  That worked for me.

     

    Traditional Excel's array handling is about as user-friendly as a cornered rat but still better than absolute/relative/mixed referencing!

     

    • vicvanlint's avatar
      vicvanlint
      Copper Contributor

      PeterBartholomew1 

      I have the same problem with Windows 10 and Basic 2019 365, but I don't understand the answer provided, and I have 365, I think.

      The first time it worked  on a 3x3 array using MINVERSE(array) with CTRL SHFT Insert.

      Then I tried it on a 2x2 array.  It entered only the first element in the output array.

      I tried copying the same 3x3 array to another location.  This time MINVERSE either delivers only one element or produces an error.

       

      • SergeiBaklan's avatar
        SergeiBaklan
        Diamond Contributor

        vicvanlint 

        In Excel 365 if you use Ctrl+Shift+Enter only first element of the array is returned. Try with simple Enter.

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