Forum Discussion
INDEX...retrun the closesed value
I try to have returned the value coming most closeley to the value in the matrix:
Specifically, I try to define an insulation thickness of the pipe, depending on diameter and operating temperature :
How can I define the formular so that a thickness is defined, if the operating value does not exactly match any of the values of the matrix, but is between two of them?
example: if Ø508 and Temp. 380, the vlaue to be returned should be 180
Thank you!
helmut
=INDEX($C$2:$I$11,MATCH(B15,$B$2:$B$11,0),MATCH(B16,$C$1:$I$1,-1))
Maybe with this formula as shown in the attached file.
5 Replies
- hansleroyIron Contributor
HiHelmut0806 ,
If you order the values in ascending order, I can think of a solution in two steps: list intermediate values, and search them with HLOOKUP.
Kind regards
Hans
- Helmut0806Copper ContributorDankeschön!
First solution helped already; it was the "-1" missing 😉- SergeiBaklanDiamond Contributor
-1 returns next smaller item, not the closest one. If you are 365 or 2021 that could be like
=XLOOKUP( 0, ABS( $B$17 - $B$3:$B$14), XLOOKUP(0,ABS(B16-$C$2:$L$2),$C$3:$L$14,,1),,1 )for
or its equivalent for previous Excel versions.
- OliverScheurichGold Contributor
=INDEX($C$2:$I$11,MATCH(B15,$B$2:$B$11,0),MATCH(B16,$C$1:$I$1,-1))
Maybe with this formula as shown in the attached file.
- Helmut0806Copper Contributorthank you! 🙂