Forum Discussion

phantom2000's avatar
phantom2000
Copper Contributor
Jan 04, 2022

Get file name from FTP Server

Hello, 

 

I am using below code to query an FTP folder and get the name of the existing file. However, I am not getting the desired output. I get some unwanted results from the code. I appreciate some help in getting the file name only. 

 

Code:

 

 

$username='Th1sUser'
$password='Th1sPas3'
$ftpuri='ftp://repo.ftpserver.com/Installer'

$uri=[system.URI] $ftpuri
$ftprequest=[system.net.ftpwebrequest]::Create($uri)

$ftprequest.Credentials=New-Object System.Net.NetworkCredential($username,$password)

$ftprequest.Method=[system.net.WebRequestMethods+ftp]::ListDirectory
$response=$ftprequest.GetResponse()
$strm=$response.GetResponseStream()

$reader=New-Object System.IO.StreamReader($strm,'UTF-8')
$list=$reader.ReadToEnd()

Write-Host "$list"

 

 

Result:

 

 

Installer/.
Installer/..
Installer/Installerv1.exe

 

 

I would like to get the installerv1.exe as the file name. Also is there a possibility to get the most recent .exe name from that directory and get that file name? Thank you in advance. 

PowerShell
windows
  • Harm_Veenstra's avatar
    Harm_Veenstra
    MVP
    Jan 17, 2022

    phantom2000 

     

    Tried it myself, used the $ftprequest.Method=[system.net.WebRequestMethods+ftp]::ListDirectoryDetails to get timestamps but not easy to parse those. Then I read a post (https://stackoverflow.com/questions/40845688/download-most-recent-file-from-ftp-using-powershell) about using WinSCP as client which gives you more options. Also a link below in the same article with even more  code  https://winscp.net/eng/docs/script_download_most_recent_file 

     

     

     

    # Load WinSCP .NET assembly
Add-Type -Path "WinSCPnet.dll"

# Setup session options
$sessionOptions = New-Object WinSCP.SessionOptions -Property @{
    Protocol = [WinSCP.Protocol]::Ftp
    HostName = "example.com"
    UserName = "user"
    Password = "mypassword"
}

$session = New-Object WinSCP.Session

# Connect
$session.Open($sessionOptions)

# Get list of files in the directory
$directoryInfo = $session.ListDirectory($remotePath)

# Select the most recent file
$latest =
    $directoryInfo.Files |
    Where-Object { -Not $_.IsDirectory } |
    Sort-Object LastWriteTime -Descending |
    Select-Object -First 1

# Any file at all?
if ($latest -eq $Null)
{
    Write-Host "No file found"
    exit 1
}

# Download the selected file
$sourcePath = [WinSCP.RemotePath]::EscapeFileMask($remotePath + $latest.Name)
$session.GetFiles($sourcePath, $localPath).Check()

     

     

    This piece of code was written by the author of WinSCP (Martin Prikryl ) , so I know it's good 🙂 

  • SteveMacNZ's avatar
    SteveMacNZ
    Iron Contributor
    Jan 17, 2022

    phantom2000 

    you could also try using split as well to split out the filename from the path. I use the below script in my scripts to create a batch name using the filename without the extension

     

     

    $BatchNameTemp      = $Script:File.split("\")[-1]
$Script:BatchName   = $BatchNameTemp.substring(0,($BatchNameTemp.length-4))

     

    so you could modify your script to 

     

    $FName = $list.split("/")[-1]

     

     

     

    • Jonathan_Allen's avatar
      Jonathan_Allen
      Brass Contributor
      Feb 04, 2022

      SteveMacNZ 

      It's well worth using split-path to separate files names and file paths..

      # to get the file name
split-path "C:\windows\system32\notepad.exe" -Leaf

# result
# notepad.exe

# to get the directory
split-path "C:\windows\system32\notepad.exe" -Parent

# result
# C:\windows\system32

Share

Resources