Forum Discussion
sum by color when colors are set by conditional formatting
- Jan 19, 2017
Hi matt nipper,
since you mentioned that you "have done an exhaustive search online" i have come up with a solution for you, although it has two limitations A) it will only work, if your rules of conditional formatting is created using conditional formatting rules with formula aka (use a formula to determine which cells to format) and B) the UDF will only work if sum range is more than one cell another word, it will not sum a single cell, as well as the conditional formatted range is more than one cell.
the example file, you can download it from here. I could not upload it here, as it is a Excel Macro-enabled Workbook that contains the UDF
Function SumConditionColorCells(CellsRange As Range, ColorRng As Range) Dim Bambo As Boolean Dim dbw As String Dim CFCELL As Range Dim CF1 As Single Dim CF2 As Double Dim CF3 As Long Bambo = False For CF1 = 1 To CellsRange.FormatConditions.Count If CellsRange.FormatConditions(CF1).Interior.ColorIndex = ColorRng.Interior.ColorIndex Then Bambo = True Exit For End If Next CF1 CF2 = 0 CF3 = 0 If Bambo = True Then For Each CFCELL In CellsRange dbw = CFCELL.FormatConditions(CF1).Formula1 dbw = Application.ConvertFormula(dbw, xlA1, xlR1C1) dbw = Application.ConvertFormula(dbw, xlR1C1, xlA1, , ActiveCell.Resize(CellsRange.Rows.Count, CellsRange.Columns.Count).Cells(CF3 + 1)) If Evaluate(dbw) = True Then CF2 = CF2 + CFCELL.Value CF3 = CF3 + 1 Next CFCELL Else SumConditionColorCells = "NO-COLOR" Exit Function End If SumConditionColorCells = CF2 End Function
in the attached example file you can see that from A3:G16 cells are formatted using Conditional Formatting.
User Defined Function (UDF) is placed in cells J2 & J3 and cells I2 and I3 are the criteria color used as reference inside the UDF in J2 and J3.
I hope this helps you.
Edit: uploaded file and updated the code to the correct one.
Hi Michael,
Ok. Can you please replace the previous UDF with this one attached below. This should fix the problem.
Please let me know how it goes.
Function SumConditionColorCells(CellsRange As Range, ColorRng As Range) Dim Bambo As Boolean Dim dbw As String Dim CFCELL As Range Dim CF1 As Single Dim CF2 As Double Dim CF3 As Long Bambo = False For CF1 = 1 To CellsRange.FormatConditions.Count If CellsRange.FormatConditions(CF1).Interior.ColorIndex = ColorRng.Interior.ColorIndex Then Bambo = True Exit For End If Next CF1 CF2 = 0 CF3 = 0 If Bambo = True Then For Each CFCELL In CellsRange dbw = CFCELL.FormatConditions(CF1).Formula1 dbw = Application.ConvertFormula(dbw, xlA1, xlR1C1) dbw = Application.ConvertFormula(dbw, xlR1C1, xlA1, , ActiveCell.Resize(CellsRange.Rows.Count, CellsRange.Columns.Count).Cells(CF3 + 1)) If Evaluate(dbw) = True Then CF2 = CF2 + CFCELL.Value CF3 = CF3 + 1 Next CFCELL Else SumConditionColorCells = "NO-COLOR" Exit Function End If SumConditionColorCells = CF2 End Function
Good evening Jamil,
Do you happen to have a version of this UDF which would sum cells with a given font color rather than an interior/background color? I have tried changing the word "Interior" to "Font" in the UDF, however when I run the formula on my desired cell, it simply shows "NO-COLOR" rather than adding the cells with the desired conditionally formatted text color. Any help would be appreciated.
Regards,
-Steve
- JamilMar 22, 2018Bronze Contributor
Hi Steve,
If you mean the font color set by conditional formatting. then you can change the line
From
If CellsRange.FormatConditions(CF1).Interior.ColorIndex = ColorRng.Interior.ColorIndex Then
ToIf CellsRange.FormatConditions(CF1).Font.Color = ColorRng.Font.Color Then
Please see it in the attached sample workbook.
- Steve ThurstonMar 23, 2018Copper Contributor
Thanks Jamil, this gets me very close. However, I suppose what I really need is for this VBA to count the number of cells within the selected range if they are a certain color, not sum the values within the cells, as the values within the selected cell range are text, not numbers. What would I change in the VBA to accommodate this?
Regards,
-Steve
- JamilMar 23, 2018Bronze Contributor
Hi Steve,
I have modified the code and attached is the version that counts instead of sum.