Oct 06 2023 03:46 AM
Hello, I'm doing an excel with macros and I've encountered an error I can't solve.
When assigning a formula in VBA like this:
cb.Formula = "=FILTER(Eq_Panto[Nombre Desplegable], Eq_Panto[VAlim]='Configurador Civity LF'!TensionAlim)"
It seems to be working as intended in terms of not giving error when assigning the formula. The only big problem is that, for some reason, it adds an "@" at the beginning of the formula, so when you go and check the formula on the cell it appears like this:
=@FILTRAR(Eq_Panto[Nombre Desplegable]; Eq_Panto[VAlim]='Configurador Civity LF'!TensionAlim)
That "@" makes the function not work properly. When there's no "@" it works jsut fine. Otherwise, it only gives one of all results of the filter.
Any idea anyone??
Thanks
Oct 06 2023 03:56 AM
Hi @alexvilla00,
In Excel, when you see an "@" symbol at the beginning of a formula, it means the formula is treated as an array formula. This can sometimes affect how the formula behaves.
In your situation, if you want to remove the "@" symbol from the formula assigned via VBA, you can use the .FormulaArray property instead of the .Formula property. This change should help your formula work as expected without the "@" symbol causing any issues. So, use the following VBA code:
cb.FormulaArray = "=FILTER(Eq_Panto[Nombre Desplegable], Eq_Panto[VAlim]='Configurador Civity LF'!TensionAlim)"
This way, you should be able to assign the formula without the "@" symbol, ensuring it functions as intended.
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Leon Pavesic
(LinkedIn)
Oct 06 2023 04:01 AM
@LeonPavesic now it's showing
{=FILTRAR(Eq_Panto[Nombre Desplegable]; Eq_Panto[VAlim]='Configurador Civity LF'!TensionAlim)}
And not working properly either.
Any other ideas?
Oct 06 2023 04:38 AM
Oct 06 2023 04:41 AM - edited Oct 06 2023 04:46 AM
But that is configuration from the app, right? Is there a way of configuring that when opening my workbook? I need to use this excel using various PCs and I don't want to configure that everytime
Nevermind, that doesn't work anyway 😞
Oct 06 2023 04:52 AM
Oct 06 2023 05:01 AM
Solution@Patrick2788 I've tried but for me it's not working, maybe it's because I'm using dynamic tables, I don't know...
Either way, I've found that using "formula2" instead of "formula" works just fine.
Thanks to all of you 😄
Oct 06 2023 05:01 AM
Solution@Patrick2788 I've tried but for me it's not working, maybe it's because I'm using dynamic tables, I don't know...
Either way, I've found that using "formula2" instead of "formula" works just fine.
Thanks to all of you 😄