Selecting top numbers that contains fewer different digits from numbers list

[Ramal Huseynzade]

Hello.How can I select top  numbers from my numbers list that contains less different digits ?for example there are 5 different numbers 3333333,3330333,3330633,3330623,3330628.How can i automatically select top 2 number (3333333 and 3330333) that contains fewer different digits?Thanks

[#2]

Hi

To count unique digits for six digit numbers:

=MMULT({1,1,1,1,1,1,1},--(FREQUENCY(--MID(A1,{1;2;3;4;5;6},1),--MID(A1,{1;2;3;4;5;6},1))>0))

[#3 · Accepted solution]

See attached file.

Play with the hurdle and see how the conditional formatting changes.

[#4]

Excellent!!! Thank you very very much.

[#5]

Now i have got numbers list that contains only 2 and 3 unique digits.Can we add another parameter to this file to be able to select only some digit combinations from these numbers that contains 2-3 unique digits?For example when i add this combination 1133322 to the parameter,the numbers in this combinations (like 66888444,5577799,3366688)can be selected automatically.I have got cominations list ,i would like to add my combinations list to that paramater,not only one combination.Thank you

[#6]

You want to match patterns?

I don't think that is possible with formulas. Maybe with VBA. But that's not my field of expertise.

Thread at stackoverflow.com

[#7]

Yes, from my numbers list i would like select numbers  in patterns like these

1133322
1133323
1133332
1211113
1222213
1222223
1222231
1222232
1222233
1222333
1223222

I played with the formula that you gave and could filter and select some numbers with necessary patterns. for instance i type {1;3;5;6;7} instead of  {1;2;3;4;5;6;7} and set hurdle to 1 to get numbers like 8687888.I hide two of the numbers each time and change pattern. but it take too much time in this way.