SOLVED

Formula Help please

Copper Contributor

Afternoon Guys

 

After some advice ive been racking my brains but cant come up with a solution 

 

I have an excel sheet that I use to track which items have been installed & tested

 

In Column H is a list of items all starting with P or U some installs require a double items hence the numbers P-06.01.02 / P 07.01.02 are in the column.

 

Is there a way to count how many letter P and Letter U's are in the column based on a blank date in Column R ?

 

JohnCooper00000_0-1635090556320.png

 

 

As always any help will be greatly appreciated

 

 

3 Replies
best response confirmed by JohnCooper00000 (Copper Contributor)
Solution

@JohnCooper00000 

Does this do what you want?

=SUM((LEN(H2:H489)-LEN(SUBSTITUTE(SUBSTITUTE(H2:H489,"P",""),"U","")))*(P2:P489=""))

If you don't have Microsoft 365 or Office 2021, confirm the formula with Ctrl+Shift+Enter.

@Hans Vogelaar Thankyou, can is there a way to filter per village from Column A
After entering the formula i end up with 342 but i would like to filter on Column A (villages) and this would tell me how many P & U are left to install in the village.

Thanksyou

@JohnCooper00000 

Use this, if necessary again confirmed with  Ctrl+Shift+Enter.

 

=SUMPRODUCT((LEN(H2:H489)-LEN(SUBSTITUTE(SUBSTITUTE(H2:H489,"P",""),"U","")))*(P2:P489="")*(SUBTOTAL(103,OFFSET(H2,ROW(H2:H489)-ROW(H2),0,1))))

1 best response

Accepted Solutions
best response confirmed by JohnCooper00000 (Copper Contributor)
Solution

@JohnCooper00000 

Does this do what you want?

=SUM((LEN(H2:H489)-LEN(SUBSTITUTE(SUBSTITUTE(H2:H489,"P",""),"U","")))*(P2:P489=""))

If you don't have Microsoft 365 or Office 2021, confirm the formula with Ctrl+Shift+Enter.

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