Jun 10 2024 04:05 PM - edited Jun 10 2024 04:07 PM
With thanks to:
Peter Bartholomew; djclements
and Sergei Baklan.
I am nearly finished on this project that must find the earliest, latest and peak dates in a range of dates.
I now need to adapt the formula to be used on the Latest dates, which are always three cells on from each of the earliest dates in the range.
Will I now be able to find the latest date (by day and month only) if I can adapt the formula that was successfully deployed for Earliest dates?
This is the formula being used for identifying Earliest dates:
=AGGREGATE(15,6, $D3:$AQ3 /( (MONTH($D3:$AQ3)*100+DAY($D3:$AQ3)) = AGGREGATE(15,6,( MONTH($D3:$AQ3)*100+DAY($D3:$AQ3) )/NOT( MOD(COLUMN($D3:$AQ3),4) ),1) ),1)
Here is the table so far:
Jun 10 2024 10:09 PM
@Clive_Rabson Please see the attached file, which contains edits to both methods discussed previously...
Jun 11 2024 09:06 AM
SolutionCriteria which columns to select is in MOD( COLUMN(...
To select every 4th row in the range we may use criteria
MOD(COLUMN($D3:$AQ3) - COLUMN($D3)+1,4)=0
entire formula
=AGGREGATE(14,6, $D3:$AQ3 /( (MONTH($D3:$AQ3)*100+DAY($D3:$AQ3)) = AGGREGATE(14,6,( MONTH($D3:$AQ3)*100+DAY($D3:$AQ3) )/(MOD(COLUMN($D3:$AQ3) - COLUMN($D3)+1,4)=0),1) ),1)
Jun 11 2024 12:28 PM
@Clive_Rabson , glad to help, hope it works now.
Jun 13 2024 01:26 PM
I thought I could use one of the earlier formula suggestions from you and DJClements to obtain the PeakDate. But I just get #SPILL which is beyond me.
I need to get the date of the first peak number. In the attached sheet, for the row3 this is found in cell M3 (16) and the date is in N3 ( 08/09/2012).
I think that will be the last part of this jigsaw.
Grateful for any suggestion
Jun 14 2024 05:58 AM
For the peak date it could be
=INDEX($D3:$AQ3, MATCH($AS3, $D3:$AQ3, 0) +1 )
and drag it down
Jun 14 2024 06:04 AM
By the way, if you have #SPILL! error that means you are on Excel 365 (or at least 2021). With that formulae could be modified, moreover we may return all result by one formula.
But since you almost finished the project, perhaps above is for future improvements.
Jun 14 2024 06:08 AM
Jun 14 2024 06:11 AM
@Clive_Rabson , you are welcome, thank you
Jun 11 2024 09:06 AM
SolutionCriteria which columns to select is in MOD( COLUMN(...
To select every 4th row in the range we may use criteria
MOD(COLUMN($D3:$AQ3) - COLUMN($D3)+1,4)=0
entire formula
=AGGREGATE(14,6, $D3:$AQ3 /( (MONTH($D3:$AQ3)*100+DAY($D3:$AQ3)) = AGGREGATE(14,6,( MONTH($D3:$AQ3)*100+DAY($D3:$AQ3) )/(MOD(COLUMN($D3:$AQ3) - COLUMN($D3)+1,4)=0),1) ),1)