Apr 15 2019 02:36 AM
I have a column and I simply need to count them with the help of an excel formula.
I add an example excel file to explain case easy. There are some numbers which I cannot remove but also cannot count them. I need a formula for D2 I can see automatically the number of rows wihout dublicates which is 44 at this example.
Please help me if you know a way to do that.
Apr 15 2019 02:56 AM
Apr 15 2019 04:03 AM
@Sergei Baklan Hi, thanks your response first. Your formula is very helpful but I must change A2:A46 in formula every time. If I have more number in column A, I have to change formula like A2:A900;A2:A900 for 900 number. I need a constant formula for every time usage.
If someone have an idea for this pls let me know :)
Apr 15 2019 04:14 AM
@Anıl Adaş , you may use dynamic range like
=SUMPRODUCT(1/COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A))))
assuming you have no other data below in your column. Formula is in F2 attached.
Apr 15 2019 04:28 AM
@Sergei Baklan Thanks a lot for your formula its very useful. I have one more question about this case. Do you know a way to find how much dublicate I have in column A as I marked green at attached example.
Apr 15 2019 04:43 AM
Actually I can easily find the number of dublicates like "total number of Column A - total number without dublicates" but is it possible to calculate doing opposite like "total number of Column A - dublicates"
Its hard to explain why but actually I exactly need to find a formula for D7 on yellow marked line on this example file.
Apr 15 2019 05:21 AM
Solution@Anıl Adaş , if calculate how many values have duplicates, that's
=SUMPRODUCT((A2:INDEX(A:A,COUNTA(A:A))<>"")/COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A))&"")-
(COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A))&"")=1))
That means if, for example, value ABC is repeated 4 times and other have no duplicates, formula returns 1 since that's only one value has duplicates.
In your case it could be simplified to
=SUMPRODUCT(1/COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A)))-(COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A)))=1))
assuming you have no blank cells within the range.
If you have ABC repeated 4 times and one XYZ, when
total = 5
with duplicates = 1
count ignoring duplicates = 2
Apr 15 2019 11:45 PM
Hi sergei, your formula was very helpful but I wanna ask you one more thing about this case. If I add a new column and say X to every row, and after than add some Y is it possible to make this calculation for A and B separately like attached example. If I keep continue to use your formula, its gonna calculate for all numbers in column B and cannot separate X and Y. I basicly tried to add an IF to make calculation separately but it didn't work.
Apr 16 2019 07:15 AM
total
=COUNTIF($A2:INDEX($A:$A,COUNTA($B:$B)),$E$4)
with duplicates
=SUMPRODUCT(($A2:INDEX($A:$A,COUNTA($B:$B))=$E$4)/ COUNTIFS($B2:INDEX($B:$B,COUNTA($B:$B)), $B2:INDEX($B:$B,COUNTA($B:$B)), $A2:INDEX($A:$A,COUNTA($B:$B)), $A2:INDEX($A:$A,COUNTA($B:$B)) ) - (COUNTIFS($B2:INDEX($B:$B,COUNTA($B:$B)), $B2:INDEX($B:$B,COUNTA($B:$B)), $A2:INDEX($A:$A,COUNTA($B:$B)), $E$4)*($A2:INDEX($A:$A,COUNTA($B:$B))= $E$4)=1))
without duplicates
=SUMPRODUCT(($A2:INDEX($A:$A,COUNTA($B:$B))=$E$4)/ COUNTIFS($B2:INDEX($B:$B,COUNTA($B:$B)), $B2:INDEX($B:$B,COUNTA($B:$B)), $A2:INDEX($A:$A,COUNTA($B:$B)), $A2:INDEX($A:$A,COUNTA($B:$B)) ))
Apr 15 2019 05:21 AM
Solution@Anıl Adaş , if calculate how many values have duplicates, that's
=SUMPRODUCT((A2:INDEX(A:A,COUNTA(A:A))<>"")/COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A))&"")-
(COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A))&"")=1))
That means if, for example, value ABC is repeated 4 times and other have no duplicates, formula returns 1 since that's only one value has duplicates.
In your case it could be simplified to
=SUMPRODUCT(1/COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A)))-(COUNTIF(A2:INDEX(A:A,COUNTA(A:A)),A2:INDEX(A:A,COUNTA(A:A)))=1))
assuming you have no blank cells within the range.
If you have ABC repeated 4 times and one XYZ, when
total = 5
with duplicates = 1
count ignoring duplicates = 2