Jul 26 2018
11:37 AM
- last edited on
Jul 12 2019
11:12 AM
by
TechCommunityAP
Jul 26 2018
11:37 AM
- last edited on
Jul 12 2019
11:12 AM
by
TechCommunityAP
I am trying write a nested IF statement that based on reading the value of % in column BR, will return a statement based on the value bucket it falls into:
Greater than 5%
Between 2.51% and 5%
Between 0% and 2.5%
Between -2% and 0%
Between -2.01% and -5%
Greater than -5%
This is the formula I've written:
=IF(BR5>=5%),"Greater than 5%",IF(AND(BR5>=2.5%,BR5<5%),"Between 2.5% and 5%",IF(AND(BR5>0%,BR5<2.5%),"Between 0% and 2.5%",IF(BR5=0%),"No Assignment",IF(AND(BR5<0%,BR5>-2%),"Between 0% and -2%",IF(AND(BR5<=-2%,BR5>=-5%),"Between -2% and -5%",IF(AND(BR5<-5.01%),""))))))
But I continue to get the error message : "There is a problem with this formula etc... 1+1
Please help!! Thank you!
Jul 26 2018 11:44 AM
I don't see how you ended your IF condition? What's your criteria? IF condition xyz is found THEN ... "Pass" else "Fail." What's your condition?
Jul 26 2018 12:55 PM
Solution=IF(BR5>=5%,"Greater than 5%", IF(AND(BR5>=2.5%,BR5<5%),"Between 2.5% and 5%", IF(AND(BR5>0%,BR5<2.5%),"Between 0% and 2.5%", IF(BR5=0%,"No Assignment", IF(AND(BR5<0%,BR5>-2%),"Between 0% and -2%", IF(AND(BR5<=-2%,BR5>=-5%),"Between -2% and -5%", IF(AND(BR5<-5.01%),"") ))))))
Jul 26 2018 01:40 PM
That didn't answer her question.
Jul 26 2018 01:54 PM
Thank you SO MUCH! This worked perfectly!
Jul 26 2018 02:28 PM
You are welcome
Jul 26 2018 12:55 PM
Solution=IF(BR5>=5%,"Greater than 5%", IF(AND(BR5>=2.5%,BR5<5%),"Between 2.5% and 5%", IF(AND(BR5>0%,BR5<2.5%),"Between 0% and 2.5%", IF(BR5=0%,"No Assignment", IF(AND(BR5<0%,BR5>-2%),"Between 0% and -2%", IF(AND(BR5<=-2%,BR5>=-5%),"Between -2% and -5%", IF(AND(BR5<-5.01%),"") ))))))