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Sue_Simmonds's avatar
Sue_Simmonds
Copper Contributor
Mar 08, 2022
Solved

Blank cell after formula

I am trying to return a blank cell in place of #DIV/0! where there are no numbers in Cube 1/2/3 cells - I have tried to use two formulas, AVERAGE and IF but it's not working, please assist??

   7 Days14 Days28 Days
Average MPa (7 days)Average MPa (14 days)Average MPa (28 days)Cube 1Cube 2Cube 3Cube 1Cube 2Cube 3Cube 4Cube 5Cube 6
#DIV/0!40.6#DIV/0!          41.3       40.4       40.2   
#DIV/0!39.2#DIV/0!          40.3       38.7       38.7   
34.0#DIV/0!#DIV/0!33.934.533.5      
33.7#DIV/0!#DIV/0!33.432.934.9      
#DIV/0!#DIV/0!40.1             39.6       39.8       40.8
#DIV/0!#DIV/0!40.2             39.2       40.1       41.4

7 Replies

    • Sue_Simmonds's avatar
      Sue_Simmonds
      Copper Contributor
      Hello Riny - many thanks for coming online to assist me.

      My current formula is basic - +AVERAGE(J8:L8) - would it need to look like this - =IFERROR(< AVERAGE(J8:L8)>,"")

      tA
      sUE

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